Использует тактику «разделяй и властвуй».
Set i = list first element index , j = list last element index
Set list item at position i = min(list value at position i, list value at position j)
Set list item at position j = max(list value at position i, list value at position j)
If (j - i) <= 1 return sorted list
Else Set t = (j - i + 1) / 3
Call sort with {i = i, j = j - t} then {i = i + t, j = j } then {i = i, j = j - t}
Допустим, я хочу отсортировать массив [1,4,5,3,-6,3,7,10,-2,-5]
, эта сортировка начнется:
Before: [1,4,5,3,-6,3,7,10,-2,-5] (i=0 ;j=9)
Before: [-5,4,5,3,-6,3,7,10,-2,1] (i=0 ;j=6)
Before: [-5,4,5,3,-6,3,7,10,-2,1] (i=0 ;j=4)
Before: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=3)
Before: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=2)
Before: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=1)
After: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=1)
Before: [-6,4,5,3,-5,3,7,10,-2,1] (i=1 ;j=2)
After: [-6,4,5,3,-5,3,7,10,-2,1] (i=1 ;j=2)
Before: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=1)
After: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=1)
After: [-6,4,5,3,-5,3,7,10,-2,1] (i=0 ;j=2)
Before: [-6,4,5,3,-5,3,7,10,-2,1] (i=1 ;j=3)
Before: [-6,3,5,4,-5,3,7,10,-2,1] (i=1 ;j=2)
After: [-6,3,5,4,-5,3,7,10,-2,1] (i=1 ;j=2)
Before: [-6,3,5,4,-5,3,7,10,-2,1] (i=2 ;j=3)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=2 ;j=3)
Before: [-6,3,4,5,-5,3,7,10,-2,1] (i=1 ;j=2)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=1 ;j=2)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=1 ;j=3)
Before: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=2)
Before: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=1)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=1)
Before: [-6,3,4,5,-5,3,7,10,-2,1] (i=1 ;j=2)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=1 ;j=2)
Before: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=1)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=1)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=2)
After: [-6,3,4,5,-5,3,7,10,-2,1] (i=0 ;j=3)
Before: [-6,3,4,5,-5,3,7,10,-2,1] (i=1 ;j=4)
Before: [-6,-5,4,5,3,3,7,10,-2,1] (i=1 ;j=3)
Before: [-6,-5,4,5,3,3,7,10,-2,1] (i=1 ;j=2)
After: [-6,-5,4,5,3,3,7,10,-2,1] (i=1 ;j=2)
Before: [-6,-5,4,5,3,3,7,10,-2,1] (i=2 ;j=3)
//etc