Нет простого способа решить вашу проблему.Вот обходной путь.
declare @t table(date datetime, id int, value int)
insert @t values('01/07/2011 00:10:00',5,200)
insert @t values('01/07/2011 00:30:00',5,210)
insert @t values('01/07/2011 00:40:00',2,458)
insert @t values('01/07/2011 00:50:00',2,500)
insert @t values('01/07/2011 01:00:00',4,600)
insert @t values('01/07/2011 01:10:00',5,359)
insert @t values('01/07/2011 01:20:00',5,360)
insert @t values('01/07/2011 01:30:00',5,370)
insert @t values('01/07/2011 01:40:00',5,380)
;with a as
(
select date, id, value, (select count(*) from @t where t.date > date) rn
from @t t
), b as
(
select a.date, a.id, a.value, coalesce(cast(b.id - a.id as bit),1) d
from a left join a b on a.rn -1 = b.rn
), c as
(
select date,id, value, (select sum(d) from b b2 where date <=b.date) e from b
)
select id, max(value) max
from c group by id, e
Результат:
id max
----- ---
5 210
2 500
4 600
5 380