Вы можете использовать pathconvert для преобразования набора файлов в список файлов, затем loadresource с filterchain для извлечения единственного требуемого значения из списка.
<project default="test">
<target name="test">
<!-- read your fileset into a property formatted as a list of lines -->
<pathconvert property="file.list" pathsep="${line.separator}">
<map from="${basedir}${file.separator}" to=""/>
<fileset dir="${basedir}">
<include name="test*.tar"/>
</fileset>
</pathconvert>
<!-- extract a single target file from the list -->
<loadresource property="file.name">
<string value="${file.list}"/>
<filterchain>
<!-- add your own logic to deal with multiple matches -->
<headfilter lines="1"/>
</filterchain>
</loadresource>
<!-- print the result -->
<echo message="file.name: ${file.name}"/>
</target>
</project>
Вывод:
$ ls test*.tar
test012.tar test123.tar testabc.tar
$
$ ant
Buildfile: C:\tmp\ant\build.xml
test:
[echo] file.name: test012.tar
BUILD SUCCESSFUL
Total time: 0 seconds
Подробный вывод:
$ ant -v
test:
[pathconvert] Set property file.list = test012.tar
[pathconvert] test123.tar
[pathconvert] testabc.tar
[loadresource] loading test012.tar
[loadresource] test123.tar
[loadresource] testabc.tar into property file.name
[loadresource] loaded 13 characters
[echo] file.name: test012.tar
BUILD SUCCESSFUL
Total time: 0 seconds