График пропускной способности Tcp

Question

Я создал программное обеспечение для чата TCP / клиент на сервере в консоли vb.net..m использование локального хоста для этой программы означает, что пакеты отправляются и принимаются с одной и той же сетевой карты. Теперь я перехватил пакеты из этого программного обеспечения на Wireshark.... и я хочу построить график пропускной способности TCp из данных, собранных на Wireshark, но у меня возникли проблемы с этим .. пожалуйста, помогите мне ..!Также научите меня, какое значение следует брать по осям x и y ..?

вот данные, которые я собрал на wireshark, поскольку я не могу различить отправленные и полученные карманы ..!

No.,"Time","Source","Destination","Protocol","Info","New Column","New Column"
1,"0.000000","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=1 Ack=1 Win=65510 Len=3","1","9050"


2,"0.441512","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=1 Ack=1 Win=65510 Len=3","2","9050"


3,"0.442643","115.186.111.66","115.186.111.66","TCP","versiera > pda-data [PSH, ACK] Seq=1 Ack=4 Win=65532 Len=3","3","3253"

4,"0.829213","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] versiera > pda-data [PSH, ACK] Seq=1 Ack=4 Win=65532 Len=3","4","3253"

5,"0.949875","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [ACK] Seq=4 Ack=4 Win=65507 Len=0","5","9050"

6,"1.259930","115.186.111.66","115.186.111.66","TCP","[TCP Dup ACK 5#1] pda-data > versiera [ACK] Seq=4 Ack=4 Win=65507 Len=0","6","9050"

7,"6.755535","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=4 Ack=4 Win=65507 Len=3","7","9050"

8,"7.119189","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=4 Ack=4 Win=65507 Len=3","8","9050"

9,"7.119833","115.186.111.66","115.186.111.66","TCP","versiera > pda-data [PSH, ACK] Seq=4 Ack=7 Win=65529 Len=3","9","3253"

10,"7.467483","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] versiera > pda-data [PSH, ACK] Seq=4 Ack=7 Win=65529 Len=3","10","3253"

11,"7.588601","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [ACK] Seq=7 Ack=7 Win=65504 Len=0","11","9050"

12,"7.931341","115.186.111.66","115.186.111.66","TCP","[TCP Dup ACK 11#1] pda-data > versiera [ACK] Seq=7 Ack=7 Win=65504 Len=0","12","9050"

13,"11.311228","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=7 Ack=7 Win=65504 Len=3","13","9050"

14,"11.650297","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=7 Ack=7 Win=65504 Len=3","14","9050"

15,"11.650931","115.186.111.66","115.186.111.66","TCP","versiera > pda-data [PSH, ACK] Seq=7 Ack=10 Win=65526 Len=3","15","3253"

16,"11.953358","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] versiera > pda-data [PSH, ACK] Seq=7 Ack=10 Win=65526 Len=3","16","3253"

17,"12.114983","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [ACK] Seq=10 Ack=10 Win=65501 Len=0","17","9050"

18,"12.388906","115.186.111.66","115.186.111.66","TCP","[TCP Dup ACK 17#1] pda-data > versiera [ACK] Seq=10 Ack=10 Win=65501 Len=0","18","9050"

19,"18.455431","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=10 Ack=10 Win=65501 Len=3","19","9050"

20,"18.699858","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=10 Ack=10 Win=65501 Len=3","20","9050"

Извините, я не могу найти лучший способ, чем это, чтобы опубликовать здесь мои данные Wirehsrak: -O

Answer 1

Поскольку вы отслеживаете разговор между вашим ПК и самим собой, да, это усложнит процесс. Как правило, если вы являетесь источником, то вы отправляете, если вы являетесь получателем, то вы получаете.

Я бы предположил, что ось X - это время, ось Y - это пропускная способность.