Я думаю, что вы хотите проанализировать Request-URI .
Вот один из способов сделать это на C ++:
#include <iostream>
#include <string>
// Returns the relative Request-URI from url. For example, given the url
// "http://www.google.com/search?q=xyz", it will return "/search?q=xyz".
//
// url need not be prefixed with a protocol; i.e. "google.com" is valid.
//
// If url contains a protocol (i.e. "http://"), the Request-URI begins with the
// first "/" after the protocol. Otherwise, the Request-URI begins with the
// first "/".
//
// If url does not contain a Request-URI, its Request-URI is "/", the server
// root.
std::string ParseRequestUri(const std::string& url) {
const std::string protocol_identifier("://");
std::size_t pos = url.find(protocol_identifier);
if (pos != std::string::npos)
pos = url.find_first_of("/", pos + protocol_identifier.length());
else
pos = url.find_first_of("/");
if (pos != std::string::npos)
return url.substr(pos);
return "/";
}
int main() {
const std::string test_url = "http://google.com/search?hl=en&source=hp&biw=1422&bih=700&q=blabla&btnG=Google+Search&aq=f&aqi=&aql=&oq=";
const std::string test_url2 = "example.com/path/to/foo/bar/baz.tar.gz";
std::cout << ParseRequestUri(test_url) << std::endl;
std::cout << ParseRequestUri(test_url2) << std::endl;
}
Приведенный выше код выведет:
/search?hl=en&source=hp&biw=1422&bih=700&q=blabla&btnG=Google+Search&aq=f&aqi=&aql=&oq=
/path/to/foo/bar/baz.tar.gz