Вы можете сделать это следующим образом, используя PIVOT
и CTE
;with cte as
(
--wrap you existing query
)
SELECT
[0], [1], [2], [3], [4]
FROM
(select Period, OrderValue from cte) AS SourceTable
PIVOT
(
max(OrderValue)
FOR Period IN ([0], [1], [2], [3], [4])
) AS PivotTable;
Ваша процедура должна выглядеть следующим образом.
ALTER PROCEDURE [dbo].[sp_GetInvoicedPayments]
@CustomerID int
AS
BEGIN
DECLARE @endOfCurrentMonth DATE = EOMONTH(GETDATE())
;with CTE AS
(
SELECT [data].CustomerID, [data].[Period], SUM([data].OrderValue) AS
OrderValue
FROM (
SELECT pms.CustomerID, pms.OrderValue,
CASE
WHEN ((SELECT CAST(pms.ExpectedDate AS DATE)) <= paymentInfo.CurrentDueMonth) THEN 0
WHEN ((SELECT CAST(pms.ExpectedDate AS DATE)) <= DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0, DATEADD(MONTH, 1, paymentInfo.CurrentDueMonth)) + 1,- 1)) ) THEN 1
WHEN ((SELECT CAST(pms.ExpectedDate AS DATE)) <= DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0, DATEADD(MONTH, 2, paymentInfo.CurrentDueMonth)) + 1,- 1))) THEN 2
WHEN ((SELECT CAST(pms.ExpectedDate AS DATE)) <= DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0, DATEADD(MONTH, 3, paymentInfo.CurrentDueMonth)) + 1,- 1))) THEN 3
WHEN ((SELECT CAST(pms.ExpectedDate AS DATE)) <= DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0, DATEADD(MONTH, 4, paymentInfo.CurrentDueMonth)) + 1,- 1))) THEN 4
END AS [Period]
FROM PaymentMilestoneSummary pms
INNER JOIN (
SELECT cus.ID AS CustomerID,
CASE
WHEN cus.PaymentStatusID = 1 THEN @endOfCurrentMonth
WHEN cus.PaymentStatusID = 2 THEN (SELECT CAST(DATEADD(month, - 1, @endOfCurrentMonth) AS DATE))
WHEN cus.PaymentStatusID = 3 THEN (SELECT CAST(DATEADD(month, - 2, @endOfCurrentMonth) AS DATE))
WHEN cus.PaymentStatusID = 4 THEN (SELECT CAST(DATEADD(month, - 3, @endOfCurrentMonth) AS DATE))
WHEN cus.PaymentStatusID = 5 THEN (SELECT CAST(DATEADD(month, - 4, @endOfCurrentMonth) AS DATE))
END AS CurrentDueMonth
FROM Company cus
) paymentInfo ON pms.CustomerID = paymentInfo.CustomerID AND paymentInfo.CustomerID= @CustomerID
)[data]
GROUP BY [data].CustomerID, [data].[Period]
)
SELECT [0], [1], [2], [3], [4]
FROM
(select Period, OrderValue from cte) AS SourceTable
PIVOT
(
max(OrderValue)
FOR Period IN ([0], [1], [2], [3], [4])
) AS PivotTable;
END
Редактировать:
как бы я суммировал те значения, которые я получил из этой строки?
Чтобы подвести итог, вы можете изменить сводный запрос следующим образом.
SELECT
[0], [1], [2], [3], [4] , s as [Sum]
FROM
(select Period, OrderValue, sum(OrderValue) over() s from cte) AS SourceTable
PIVOT
(
max(OrderValue)
FOR Period IN ([0], [1], [2], [3], [4])
) AS PivotTable;