Да, вы можете использовать обратные вызовы (https://www.tensorflow.org/api_docs/python/tf/keras/callbacks/Callback). Например:
import tensorflow as tf
class PrintLogs(tf.keras.callbacks.Callback):
def __init__(self, epochs):
self.epochs = epochs
def set_params(self, params):
params['epochs'] = 0
def on_epoch_begin(self, epoch, logs=None):
print('Epoch %d/%d' % (epoch + 1, self.epochs), end='')
mnist = tf.keras.datasets.mnist
(x_train, y_train),(x_test, y_test) = mnist.load_data()
x_train, x_test = x_train / 255.0, x_test / 255.0
model = tf.keras.models.Sequential([
tf.keras.layers.Flatten(input_shape=(28, 28)),
tf.keras.layers.Dense(512, activation=tf.nn.relu),
tf.keras.layers.Dropout(0.2),
tf.keras.layers.Dense(10, activation=tf.nn.softmax)
])
model.compile(optimizer='adam',
loss='sparse_categorical_crossentropy',
metrics=['accuracy'])
epochs = 5
model.fit(x_train, y_train,
epochs=epochs,
validation_split=0.2,
verbose = 2,
callbacks=[PrintLogs(epochs)])
выход:
Train on 48000 samples, validate on 12000 samples
Epoch 1/5 - 10s - loss: 0.0306 - acc: 0.9901 - val_loss: 0.0837 - val_acc: 0.9786
Epoch 2/5 - 9s - loss: 0.0269 - acc: 0.9910 - val_loss: 0.0839 - val_acc: 0.9788
Epoch 3/5 - 9s - loss: 0.0253 - acc: 0.9915 - val_loss: 0.0895 - val_acc: 0.9781
Epoch 4/5 - 9s - loss: 0.0201 - acc: 0.9930 - val_loss: 0.0871 - val_acc: 0.9792
Epoch 5/5 - 9s - loss: 0.0206 - acc: 0.9931 - val_loss: 0.0917 - val_acc: 0.9793