Как пропустить задание, когда условие не выполнено

Question

Роль со следующей задачей, которая должна создать задание cron, если my_environment var is "prod" .

Я бы хотел, чтобы пьеса была пропустить эту задачу, а не выполнить ее, если условие не выполнено:

---
- name: Configure cron job to export patch logs
  cron:
    name: export patch logs daily
    minute: 0
    hour: 0
    user: root
    cron_file: patch_logs
    job: "/usr/local/bin/aws s3 cp /var/log/dpkg.log s3://{{ patch_logs_bucket }}/dpkg.log.$(hostname).$(date +\\%F)"
  when: my_environment == "prod"

Сообщение об ошибке:

TASK [ansible-contxt-base : Configure cron job to export patch logs] ***********
    fatal: [ubuntu-1604]: FAILED! => {"msg": "The conditional check 'scx_environment == \"prod\"' failed. The error was: error while evaluating conditional (scx_environment == \"prod\"): 'my_environment' is undefined\n\nThe error appears to have been in '/**<path>**/tasks/base.yml': line 125, column 3, but may\nbe elsewhere in the file depending on the exact syntax problem.\n\nThe offending line appears to be:\n\n\n- name: Configure cron job to export patch logs\n  ^ here\n"}

Answer 1

Мы можем использовать ярлык jinja2 для «default (False)»: «d (False)».

when: my_environment|d(False) == "prod"

Answer 2

найдено здесь https://ansible -docs.readthedocs.io / zh / stable-2.0 / rst / playbooks_conditionals.html # the-when-Statement

- shell: echo "This certainly isn't epic!"
  when: not epic

или

- fail: msg="Bailing out. this play requires 'bar'"
  when: bar is undefined

Answer 3

when:

my_environment is defined

my_environment != ”prod”