Я тестировал это решение с MySQL, но оно должно работать на любом движке SQL.
Данные испытаний:
CREATE TABLE test_date (
date date NOT NULL
);
INSERT INTO test_date VALUES
('2019-03-01'),
('2019-03-20'),
('2019-03-21'),
('2019-03-22'),
('2019-03-23'),
('2019-03-24'),
('2019-03-25'),
('2019-03-26');
Запрос на получение ваших данных:
SELECT
td2.date,
/*
To calculate remaining of a weekday, you can then use this formula:
if desired_week_day_number > week_day_number
and desired_week_day_number <= (week_day_number + remaining_days_after_weeks):
remaining_weeks + 1
elseif desired_week_day_number <= (week_day_number + remaining_days_after_weeks - 7):
remaining_weeks + 1
else remaining_weeks
*/
CASE WHEN (1 > td2.week_day_number AND 1 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 1 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_sundays,
CASE WHEN (2 > td2.week_day_number AND 2 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 2 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_mondays,
CASE WHEN (3 > td2.week_day_number AND 3 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 3 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_tuesdays,
CASE WHEN (4 > td2.week_day_number AND 4 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 4 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_wednesdays,
CASE WHEN (5 > td2.week_day_number AND 5 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 5 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_thursdays,
CASE WHEN (6 > td2.week_day_number AND 6 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 6 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_fridays,
CASE WHEN (7 > td2.week_day_number AND 7 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 7 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_saturdays,
td2.*
FROM (
SELECT
td.date,
day(td.date) day_number,
dayofweek(td.date) week_day_number,
dayname(td.date) week_day_name,
day(last_day(td.date)) nb_month_days,
day(last_day(td.date)) - day(td.date) remaining_days,
floor((day(last_day(td.date)) - day(td.date)) / 7) remaining_weeks,
day(last_day(td.date)) - day(td.date) -
floor((day(last_day(td.date)) - day(td.date)) / 7) * 7 remaining_days_after_weeks
FROM test_date td
) AS td2
ORDER BY td2.date;
Вы можете включить точно такую же вещь в оператор обновления соответствующим образом.
Конечно, это можно сделать намного короче / проще, если вы поместите дни недели в подзапрос / таблицу, избегая повторения формулы для каждого дня недели, но сейчас я предоставлю вам это упражнение. ;-) Основная задача состояла в том, чтобы выяснить, как рассчитать остаток от данного дня недели.