Благодаря Андреасу я наконец нашел решение для обработки огромного XML-файла и преобразования xml-элементов соответствий в JSON.
String testCars = "<root><car><name>car1</name></car><other><something>Unknown</something></other><car><name>car2</name></car></root>";
String startElement = "car";
int volgnummer = 1;
XMLInputFactory factory = XMLInputFactory.newInstance();
try {
XMLStreamReader streamReader = factory.createXMLStreamReader(new StringReader(testCars));
streamReader.nextTag();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty("omit-xml-declaration", "yes");
streamReader.nextTag();
while ( streamReader.isStartElement() ||
( ! streamReader.hasNext() &&
streamReader.nextTag() == XMLStreamConstants.START_ELEMENT)) {
StringWriter writer = new StringWriter();
StreamResult result = new StreamResult(writer);
t.transform(new StAXSource(streamReader), result);
JSONObject jsonObject = XML.toJSONObject(writer.toString());
jsonObject.put("sequence", ++volgnummer);
System.out.println("XmlChunkToJson: " + jsonObject.toString());
}
} catch (Exception e) {
e.printStackTrace();
}
Ввод XML:
<?xml version="1.0"?>
<root>
<car>
<name>car1</name>
</car>
<other>
<something>Unknown</something>
</other>
<car>
<name>car2</name>
</car>
</root>
Вывод JSON:
XmlChunkToJson: {"sequence":2,"car":{"name":"car1"}}
XmlChunkToJson: {"sequence":3,"other":{"something":"Unknown"}}
XmlChunkToJson: {"sequence":4,"car":{"name":"car2"}}