Внутри функции setUp () я хочу использовать класс PDOMock, определенный следующим образом
namespace TddProject;
class PDOMock extends \PDO
{
public function __construct() {}
}
Но когда я запускаю тест, я получаю эту ошибку:
Argument 1 passed to TddProject\InvoiceManager::__construct() must be an instance of PDO, instance of Mock_PDOMock_7d3c9396 given, called in /Applications/MAMP/htdocs/tdd_project/tests/InvoiceManagerTest.php on line 35 and defined
/Applications/MAMP/htdocs/tdd_project/src/InvoiceManager.php:16
Класс InvoiceManager имеет этот конструктор:
public function __construct(\PDO $db)
{
$this->db = $db;
}
Кажется, PDOMock не виден. Можете ли вы предложить мне, как решить эту проблему?
спасибо
EDIT:
вот полный тестовый класс:
<?php
use TddProject\Customer;
use TddProject\Invoice;
use TddProject\InvoiceManager;
class InvoiceManagerTest extends PHPUnit_Framework_TestCase
{
private $stmMock;
private $pdoMock;
public function setUp()
{
$this->stmMock = $this->getMock('PDOStatement', array('execute','fetch'));
$this->stmMock->expects($this->any())->method('execute')
->will($this->returnValue(true));
$this->pdoMock = $this->getMock('PDOMock', array('prepare','lastInsertId'));
$this->pdoMock->expects($this->any())->method('prepare')
->will($this->returnValue($this->stmMock));
}
public function testRaiseInvoice() {
$this->pdoMock->expects($this->once())
->method('lastInsertId')->will($this->returnValue(1));
$invoiceManager = new InvoiceManager($this->pdoMock);
$product1 = new \TddProject\Product();
$product1->price = 10;
$product1->product_id = 1;
$customer = new Customer();
$customer->customer_id = 1;
$invoice = new Invoice();
$productsArray = array(array(
'product' => $product1,
'quantity' => 2
));
$invoiceManager->raiseInvoice($invoice, $customer, $productsArray);
$this->assertEquals(20, $invoice->price_total);
}
}