Ваша проблема в том, что ваши значения длиннее , чем заданные строки формата:
*155sfjfnfjv7qeeefefefe*
123456789012345678901234 # 24 characters long
{:>12} {:>12} {:>8} {:>12} # 1st data point is 12 chars aligned, but
# too long so remaining text gets shoved
Вы можете настроить печать на самое длинное значение каждой клавиши.У вас нет недостающих ключей - это может выглядеть так:
data = [{"Change Id": "155sfjfnfjv7qeeefefefe", "Service": "*test2121_dkfdb*",
"TRS Environment": "*prod*", "Audit": "<localhost:9090>"},
{"Change Id": "*15sldjnfs56766qedeq*", "Service":"*testkbhhb_236r526ffdf*",
"TRS Environment":"*prod*","Audit":"<localhost:9090:123>"},
{"Change Id":"*155aoufheufh788478*","Service":"*testfdjhg*",
"TRS Environment":"*prod*","Audit":"<locaefbhlkf:23526/kdjfg/kfhgb/lkrfbjke/kj>"} ]
# for each dict of your data, for each key, get the length and store
# the maximum length over all dicts values for that key
lengths = {}
for d in data:
for key,value in d.items():
lengths.setdefault(key,0) # store the lenght of the value under this keys name
lengths[key] = max(lengths[key],len(value)) # keep the max length for this key
# order of data printout by keyname
order = [ "Change Id","Service","TRS Environment","Audit"]
# for each dict in data print (in the order of keys wanted)
for d in data:
for o in order:
# one key spaced by its maximum length+4 over all dicts
print(f"{o}: {d[o]:{lengths.get(o) + 4}}", end="")
print() # add newline
Вывод:
Change Id: 155sfjfnfjv7qeeefefefe Service: *test2121_dkfdb* TRS Environment: *prod* Audit: <localhost:9090>
Change Id: *15sldjnfs56766qedeq* Service: *testkbhhb_236r526ffdf* TRS Environment: *prod* Audit: <localhost:9090:123>
Change Id: *155aoufheufh788478* Service: *testfdjhg* TRS Environment: *prod* Audit: <locaefbhlkf:23526/kdjfg/kfhgb/lkrfbjke/kj>