Мы можем перебрать list
и удалить подстроку либо substring
, либо str_remove
library(tidyverse)
map_df(results, ~ .x %>%
mutate_at(vars(matches('^var\\d+$')),
list(~ str_remove(., "^UniRef90_"))))
# var1 var2 corr
#1 A0A075GGL3 A0A075GGW4 -0.12058932
#2 A0A075GGU1 A0A075GGW4 -0.01740142
#3 A0A075GGU4 A0A075GGW4 0.16400148
#4 A0A075GGV0 A0A075GGW4 -0.09698018
#5 A0A075GGV1 A0A075GGW4 0.22409572
#6 A0A075GGV8 A0A075GGW4 0.43184873
#7 A0A075GJW0 A0A075GKB8 -0.10590950
#8 A0A075GJW5 A0A075GKB8 -0.43363700
#9 A0A075GJX5 A0A075GKB8 -0.18758410
#10 A0A075GJY4 A0A075GKB8 0.26581490
#11 A0A075GJY8 A0A075GKB8 -0.28207920
#12 A0A075GJY9 A0A075GKB8 -0.24028270
данные
results <- list(structure(list(var1 = c("UniRef90_A0A075GGL3",
"UniRef90_A0A075GGU1",
"UniRef90_A0A075GGU4", "UniRef90_A0A075GGV0", "UniRef90_A0A075GGV1",
"UniRef90_A0A075GGV8"), var2 = c("UniRef90_A0A075GGW4",
"UniRef90_A0A075GGW4",
"UniRef90_A0A075GGW4", "UniRef90_A0A075GGW4", "UniRef90_A0A075GGW4",
"UniRef90_A0A075GGW4"), corr = c(-0.12058932, -0.01740142, 0.16400148,
-0.09698018, 0.22409572, 0.43184873)), class = "data.frame", row.names = c("4945",
"4946", "4947", "4948", "4949", "4950")),
structure(list(var1 = c("UniRef90_A0A075GJW0",
"UniRef90_A0A075GJW5", "UniRef90_A0A075GJX5", "UniRef90_A0A075GJY4",
"UniRef90_A0A075GJY8", "UniRef90_A0A075GJY9"), var2 = c("UniRef90_A0A075GKB8",
"UniRef90_A0A075GKB8", "UniRef90_A0A075GKB8", "UniRef90_A0A075GKB8",
"UniRef90_A0A075GKB8", "UniRef90_A0A075GKB8"), corr = c(-0.1059095,
-0.433637, -0.1875841, 0.2658149, -0.2820792, -0.2402827)),
class = "data.frame", row.names = c("4945",
"4946", "4947", "4948", "4949", "4950")))