как вы запрашиваете сырой SQL на рельсах?
Итак, у меня есть этот сырой sql, который мне нужен для запуска на рельсах, но с синтаксической ошибкой. Я также избегаю лишних скобок, но все еще получаю синтаксическую ошибку рядом с первым внутренним соединением.
вот мой код:
Spree::CorporateAccount.joins(" (((((
( inner join spree_memberships on spree_corporate_accounts.id = spree_memberships.corporate_account_id)
inner join spree_users on spree_memberships.user_id = spree_users.id)
left join spree_variant_price_sets on spree_corporate_accounts.variant_price_set_id = spree_variant_price_sets.id)
left join spree_addresses on spree_corporate_accounts.bill_address_id = spree_addresses.id)
left join spree_states on spree_addresses.state_id = spree_states.id)
left join spree_countries on spree_addresses.country_id = spree_countries.id)
left join spree_partner_accounts on spree_corporate_accounts.id = spree_partner_accounts.partnerable_id
").where(" spree_memberships.deleted_at IS null
AND (spree_partner_accounts.partnerable_type = 'Spree::CorporateAccount' OR spree_partner_accounts.partnerable_type IS NULL)
AND admin = true
")
но на sql это прекрасно.
SELECT
spree_corporate_accounts.id,
spree_corporate_accounts.company_name,
spree_memberships.ADMIN,
spree_users.email,
spree_users.doctor AS name,
spree_partner_accounts.account_key,
CASE spree_corporate_accounts.billing_type when 1 THEN 'Postbill' WHEN 2 THEN 'Creditcard' ELSE 'Individual'END,
spree_variant_price_sets.name AS priceset,
spree_addresses.address1,
spree_addresses.address2,
spree_addresses.city,
spree_addresses.zipcode,
spree_states.name AS state,
spree_countries.name AS country,
spree_addresses.phone,
spree_users.created_at
from (((((( spree_corporate_accounts inner join spree_memberships on spree_corporate_accounts.id = spree_memberships.corporate_account_id)
inner join spree_users on spree_memberships.user_id = spree_users.id)
left join spree_variant_price_sets on spree_corporate_accounts.variant_price_set_id = spree_variant_price_sets.id)
left join spree_addresses on spree_corporate_accounts.bill_address_id = spree_addresses.id)
left join spree_states on spree_addresses.state_id = spree_states.id)
left join spree_countries on spree_addresses.country_id = spree_countries.id)
left join spree_partner_accounts on spree_corporate_accounts.id = spree_partner_accounts.partnerable_id
where spree_memberships.deleted_at IS null
and (spree_partner_accounts.partnerable_type = 'Spree::CorporateAccount' OR spree_partner_accounts.partnerable_type IS NULL )
AND admin = true
если я сделаю это. Это даст другой результат. так что я думаю, что скобки сначала оценивают результат, а затем переходят к следующему.
Spree::CorporateAccount.joins("inner join spree_memberships on spree_corporate_accounts.id = spree_memberships.corporate_account_id")
.joins("inner join spree_users on spree_memberships.user_id = spree_users.id")
.joins("left join spree_variant_price_sets on spree_corporate_accounts.variant_price_set_id = spree_variant_price_sets.id")
.joins("left join spree_addresses on spree_corporate_accounts.bill_address_id = spree_addresses.id")
.joins("left join spree_states on spree_addresses.state_id = spree_states.id")
.joins("left join spree_countries on spree_addresses.country_id = spree_countries.id")
.joins("left join spree_partner_accounts on spree_corporate_accounts.id = spree_partner_accounts.partnerable_id ")
.where("spree_memberships.deleted_at IS null
AND spree_partner_accounts.partnerable_type = 'Spree::CorporateAccount' OR spree_partner_accounts.partnerable_type IS NULL
AND admin = true
")