У меня есть форма входа, которая работает с Firebase auth и подключается к servlet.Вопрос в том, что его отправляют дважды.Пожалуйста, проверьте ниже.
код javascript
function toggleSignIn()
{
if (firebase.auth().currentUser)
{
// [START signout]
//window.location.href = 'LoadSellPendingApprovals'
alert('existing user');
firebase.auth().signOut();
// [END signout]
} else {
var email = document.getElementById('email').value;
var password = document.getElementById('password').value;
if (email.length < 4) {
alert('Please enter an email address.');
return;
}
if (password.length < 4) {
alert('Please enter a password.');
return;
}
// Sign in with email and pass.
// [START authwithemail]
firebase.auth().signInWithEmailAndPassword(email, password).then(function(firebaseUser)
{
var email = firebase.auth().currentUser.email;
//alert(email);
// console.log(email) contains email
const options = {
method: 'POST',
//url: 'LoginValidator',
headers: {
// set appropriate headers, assuming json here
//"Content-Type": "application/json",
"Content-Type": "application/x-www-form-urlencoded"
},
// form body, assuming json
//body: JSON.stringify(email)
body: `email=${email}`
}
alert(email);
url = 'LoginValidator'
fetch(url, options)
.then(response => response.json())
.then(data => console.log(data))
. catch(e => console.error(e))
window.location.href = 'LoginValidator'
})
.catch(function(error)
{
// Handle Errors here.
var errorCode = error.code;
var errorMessage = error.message;
// [START_EXCLUDE]
if (errorCode === 'auth/wrong-password')
{
alert('Wrong password.');
} else {
alert(errorMessage);
}
console.log(error);
document.getElementById('quickstart-sign-in').disabled = false;
// [END_EXCLUDE]
});
//alert('hi');
// [END authwithemail]
}
document.getElementById('quickstart-sign-in').disabled = true;
}
Моя HTML-форма
<form id="login-form" class="form" action="" method="post">
<div class="form-group">
<input type="text" name="email" id="email" class="form-control login-input" placeholder="username">
</div>
<div class="form-group">
<input class="form-control login-input" type="password" placeholder="Password" id="password" name="password">
<i id="open" class="fa fa-eye fa-2x"></i>
<i id="closed" class="fa fa-eye-slash fa-2x"></i>
</div>
<div class="form-group">
<input type="submit" id="quickstart-sign-in" name="quickstart-sign-in" class="form-control btn btn-info btn-md login-bt" value="Login" onclick="toggleSignIn()">
</div>
<div class="form-group text-center forgot">
<a href="#">Forgot username</a> / <a href="#">password?</a>
</div>
</form>
Ниже мой сервлет (куда отправляется формак) на случай, если вы заинтересованы
public class LoginValidator extends HttpServlet {
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
String email = request.getParameter("email");
System.out.println("Printing email: "+email);
try {
System.out.println("inside try");
User user = new User();
UserRight userRight = new UserRight();
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.registerTypeAdapter(Date.class, new DateTypeDeserializer());
Gson gson = gsonBuilder.create();
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(BaseURLs.BASE_URL)
.addConverterFactory(GsonConverterFactory.create(gson))
.build();
//Get user
RestEndPointsInterface endPoint = retrofit.create(RestEndPointsInterface.class);
Call<User> call = endPoint.getUserByEmail(email);
user = call.execute().body();
System.out.println(user.getName());
//Get user rights
Call<UserRight> userRightCall = endPoint.getUserRightByID(user.getUserRights().getIduserRight());
userRight = userRightCall.execute().body();
System.out.println(userRight.getUserRight());
if(userRight.getUserRight().equals("admin"))
{
RequestDispatcher requestDispatcher = request.getRequestDispatcher("LoadSellPendingApprovals");
requestDispatcher.forward(request, response);
}
else
{
RequestDispatcher requestDispatcher = request.getRequestDispatcher("index.html");
requestDispatcher.forward(request, response);
}
} catch (Exception e) {
e.printStackTrace();
}
}
// <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
/**
* Handles the HTTP <code>GET</code> method.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
/**
* Handles the HTTP <code>POST</code> method.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
/**
* Returns a short description of the servlet.
*
* @return a String containing servlet description
*/
@Override
public String getServletInfo() {
return "Short description";
}// </editor-fold>
}
В моей консоли IDE вывод выглядит следующим образом (вывод печатается с помощью servlet)
Printing email: email@example.com
inside try
Printing email: null
inside try
java.lang.IllegalArgumentException: Path parameter "email" value must not be null.