какой дизайн должен иметь мой стол Fixture, чтобы выбрать и показать две команды из выпадающего списка?

Question

Команда таблица

   TeamID (PK)
   TeamName 
   CoachID  (FK)

Fixture Таблица

 FixtureID  (PK)
 Venue    
 Team1    (FK) to TeamTable
 Team2     (FK) to TeamTable
 FixtureDate

Я создал хранимую процедуру

CREATE PROCEDURE [dbo].[PR_Fixture_SelectAll]
AS
    SELECT
        [dbo].[Fixture].[FixtureID],
        [dbo].[Fixture].[Venue],
        [dbo].[Fixture].[Team1],
        [dbo].[Fixture].[Team2],
        [dbo].[Fixture].[FixtureDate],
        [dbo].[Team].[TeamName]
    FROM 
        [dbo].[Fixture] 
    INNER JOIN
        [dbo].[Team] ON [dbo].[Team].[TeamID] = [dbo].[Fixture].[Team1]
    INNER JOIN
        [dbo].[Team] t ON[dbo].[Team].[TeamID] = [dbo].[Fixture].[Team2]    

При выполнении хранимой процедуры отображается только имя столбца, а не вставленные данные

Answer 1

Это может помочь вам

DECLARE @Team TABLE
(
   TeamID INT  ,
   TeamName VARCHAR(50),
   CoachID INT 
)

DECLARE @Fixture Table
(

    FixtureID INT,
    Venue VARCHAR(50),
    Team1 INT ,
    Team2 INT,
    FixtureDate DATE

)

INSERT INTO @Team(TeamID,TeamName,CoachID) VALUES(1,'A',1)
INSERT INTO @Team(TeamID,TeamName,CoachID) VALUES(2,'B',2)
INSERT INTO @Team(TeamID,TeamName,CoachID) VALUES(3,'C',3)
INSERT INTO @Team(TeamID,TeamName,CoachID) VALUES(4,'D',4)

INSERT INTO @Fixture(FixtureID,Venue,Team1,Team2,FixtureDate) VALUES(1,'X',1,3,GETDATE())
INSERT INTO @Fixture(FixtureID,Venue,Team1,Team2,FixtureDate) VALUES(2,'Y',2,4,GETDATE())

SELECT
        f.FixtureID,
        f.Venue,
        t1.TeamName Team1,
        t2.TeamName Team2,
        f.FixtureDate
FROM @Fixture f
Inner Join @Team t1 ON  f.Team1 = t1.TeamID 
Inner Join @Team t2 ON  f.Team2 = t2.TeamID