Вы думали об использовании подзапросов или даже CTE?Может быть, это поможет вам найти свой ответ:
select outer.col1,
outer.col2,
outer.col3,
outer.col4,
outer.col5,
outer.col6, count(*) as cnt
from (
select <some logic> as col1,
<some logic> as col2,
<some logic> as col3,
<some logic> as col4,
<some logic> as col5,
<some logic> as col6
from innerTable
)outer
group by outer.col1,
outer.col2,
outer.col3,
outer.col4,
outer.col5,
outer.col6