JSON кодировать PHP

Question

Так вот мой код:

<?php
ini_set('max_execution_time', 150);
require('db.php');

$values = array();
$data = array();
$username = $_GET['username'];
$username = $mysqli->real_escape_string($username);
$password = $_GET['password'];
$password = $mysqli->real_escape_string($password);
$query = $mysqli->query("SELECT premium_duration, vip_duration
FROM 
users_account
WHERE 
user_name='".$username."' 
AND user_pass='".md5($password)."'
");
while($row = $query->fetch_assoc())
{
    if($row['premium_duration'] > 0)
    {
        $timeremain = $row['premium_duration'];
        $type = 'Premium';
    }elseif($row['vip_duration'] > 0)
    {
        $timeremain = $row['vip_duration'];
        $type = 'VIP';
    }else{
        $timeremain = 0;
        $type = 'None';
    }

    $values['TimeRemain'] = $timeremain;
    $values['Type'] = $type;
    $data[] = $values;  
}

echo json_encode(array("Durations" => ($data)));
?>

Но это только приводит к:

{"Durations": [{"TimeRemain": "15847800", "Type":" Premium "}]}

Чего я хочу добиться:

{" Durations "? {" TimeRemain ": 74973600," Type ":"Premium "}, {" TimeRemain ": 0," Type ":" VIP "}]}

Как я могу это сделать?