Невозможно найти столбец с логическим именем: user_details_id в org.hibernate.mapping.Table (user_details) и связанных с ним супертаблицах и вторичных таблицах. - PullRequest
0 голосов
/ 27 марта 2019

Я пытаюсь создать простое однонаправленное отображение. Я использую MappedSuperclass и @JoinColumn, и, вероятно, есть проблема. Похоже, сущность не может найти поле id из суперкласса.

Исключение:

Caused by: org.hibernate.MappingException: Unable to find column with logical name: user_details_id in org.hibernate.mapping.Table(user_details) and its related supertables and secondary tables
    at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:832) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:256) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:101) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processEndOfQueue(InFlightMetadataCollectorImpl.java:1827) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processFkSecondPassesInOrder(InFlightMetadataCollectorImpl.java:1771) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processSecondPasses(InFlightMetadataCollectorImpl.java:1658) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:287) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:904) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:935) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]

Супер класс:

@Getter
@Setter
@MappedSuperclass
public abstract class BaseEntity {

    @Id
    @GeneratedValue(
            strategy =  GenerationType.IDENTITY
    )
    private Long id;

}

Сущность сообщения (объединяет идентификаторы отправителя и получателя)

@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@Builder
@Entity(name = "Message")
@Table(name = "message")
public class Message extends BaseEntity {
    private String title;
    private String details;
    private String message_container;
    private LocalDate dataOfSending;

    @ManyToOne(optional = false)
    @JoinColumn(name = "sender_id", referencedColumnName = "user_details_id")
    private UserDetails sender;

    @ManyToOne(optional = false)
    @JoinColumn(name = "receiver_id", referencedColumnName = "user_details_id")
    private UserDetails receiver;
}

Данные пользователя (не должны знать о сообщениях)

@Getter
@Setter
@Builder
@NoArgsConstructor
@AllArgsConstructor
@Entity(name = "UserDetails")
@Table(name = "user_details")
public class UserDetails extends BaseEntity {

    private String firstName;
    private String lastName;
    private String motherName;
    private String fatherName;
    private String personalIdentityNum;
    private LocalDate dateOfBirth;

    @OneToOne
    @JoinColumn(name = "user_id")
    private User user;

    @OneToOne(mappedBy = "userDetails")
    private Address address;

    @OneToOne(mappedBy = "userDetails")
    private Contact contact;

    @OneToOne(mappedBy = "userDetails")
    private ProfileImage profileImage;

}

Есть идеи? Заранее спасибо.

1 Ответ

0 голосов
/ 27 марта 2019

Можете ли вы просто изменить этот раздел в Message классе

   @ManyToOne(optional = false)
    @JoinColumn(name = "sender_id", referencedColumnName = "user_details_id")
    private UserDetails sender;

    @ManyToOne(optional = false)
    @JoinColumn(name = "receiver_id", referencedColumnName = "user_details_id")
    private UserDetails receiver;

до

    @ManyToOne
    @JoinColumn(name = "sender_id")
    private UserDetails sender;

    @ManyToOne
    @JoinColumn(name = "receiver_id")
    private UserDetails receiver;

И в UserDetails добавьте эти коды

 @OneToMany(mappedBy = "sender")
private List<Message> senderMessage = new ArrayList<>();

@OneToMany(mappedBy = "receiver")
private List<Message> receiverMessage = new ArrayList<>();
...