что написать в views.py для реализации моего файла пути к базе данных postgreql?
def post(self,request):
file_path = request.data.get('myfiles')
generate_response = list()
with open(file_path, 'rt',) as f:
reader = csv.reader(f)
for row in reader:
print(row)
generate_response.append(row)
return Response(generate_response)
def post(self,request):
file_path = request.data.get('myfiles')
generate_response = list()
with open(file_path, 'rt',) as f:
reader = csv.reader(f)
for row in reader:
print(row)
generate_response.append(row)
return Response(generate_response)