Получить имя, дату и сумму из заказов в марте

Question

У меня есть этот запрос:

SELECT * 
FROM ((orders_books 
JOIN books ON orders_books.id_book = books.id) 
JOIN orders ON orders_books.id_order=orders.id) 
JOIN users ON user_id=users.id 
WHERE date >='2019-03-1' AND date <= '2019-03-31';

Результат запроса: https://image.prntscr.com/image/s3ngzzYrSd27mFib9HbLmA.png

Я нахожу количество заказов:

SELECT name, date, SUM(book_price) 
FROM ((orders_books 
INNER JOIN books ON orders_books.id_book = books.id) 
INNER JOIN orders ON orders_books.id_order=orders.id) 
INNER JOIN users ON user_id=users.id 
WHERE date >='2019-03-1' AND date <= '2019-03-31';

[Сумма для всех заказов]: https://image.prntscr.com/image/o88Hf4uKSHGuZ2ESUECzuA.png

Но мне нужно найти сумму заказа отдельно для каждого заказа.

Answer 1

SELECT orders.id, SUM(book_price) 
FROM ((orders_books 
INNER JOIN books ON orders_books.id_book = books.id) 
INNER JOIN orders ON orders_books.id_order=orders.id) 
INNER JOIN users ON user_id=users.id 
WHERE date >='2019-03-1' AND date <= '2019-03-31'
GROUP BY order_id;

Answer 2

Если вам нужна сумма для order.id, тогда используйте group by orders.id

    SELECT orders.id  SUM(book_price) 
    FROM orders_books 
    INNER JOIN books ON orders_books.id_book = books.id
    INNER JOIN orders ON orders_books.id_order=orders.id

    WHERE date >='2019-03-1' AND date <= '2019-03-31'
    group by orders.id

Answer 3

Как насчет:

SELECT id_order, SUM(book_price) 
FROM ((orders_books 
INNER JOIN books ON orders_books.id_book = books.id) 
INNER JOIN orders ON orders_books.id_order=orders.id) 
INNER JOIN users ON user_id=users.id 
WHERE date >='2019-03-1' AND date <= '2019-03-31'
GROUP BY id_order;