У меня есть приложение Grails 3 и подключаемый модуль (plugin1).У подключаемого модуля есть еще один подключаемый модуль, назовем его plugin2.Когда я добавляю plugin1 без plugin2, приложение запускается без проблем, но когда plugin2 добавляется в plugin1, я получаю сообщение об ошибке:
Error |
Failed to start server (NOTE: Stack trace has been filtered. Use --verbose to see entire trace.)
java.util.concurrent.ExecutionException: org.gradle.tooling.BuildException: Could not execute build using Gradle distribution 'https://services.gradle.org/distributions/gradle-3.5-all.zip'.
at java_util_concurrent_Future$get.call(Unknown Source)
at run-app.run(run-app.groovy:89)
at org.grails.cli.profile.commands.script.GroovyScriptCommand.handle(GroovyScriptCommand.groovy:152)
at org.grails.cli.profile.AbstractProfile.handleCommand(AbstractProfile.groovy:481)
at org.grails.cli.GrailsCli.handleCommand(GrailsCli.groovy:377)
at org.grails.cli.GrailsCli.handleCommand(GrailsCli.groovy:350)
at org.grails.cli.GrailsCli.execute(GrailsCli.groovy:271)
at org.grails.cli.GrailsCli.main(GrailsCli.groovy:159)
Caused by: org.gradle.tooling.BuildException: Could not execute build using Gradle distribution 'https://services.gradle.org/distributions/gradle-3.5-all.zip'.
at org.gradle.tooling.internal.consumer.ExceptionTransformer.transform(ExceptionTransformer.java:51)
at org.gradle.tooling.internal.consumer.ExceptionTransformer.transform(ExceptionTransformer.java:29)
at org.gradle.tooling.internal.consumer.ResultHandlerAdapter.onFailure(ResultHandlerAdapter.java:41)
at org.gradle.tooling.internal.consumer.async.DefaultAsyncConsumerActionExecutor$1$1.run(DefaultAsyncConsumerActionExecutor.java:57)
at org.gradle.internal.concurrent.ExecutorPolicy$CatchAndRecordFailures.onExecute(ExecutorPolicy.java:54)
at org.gradle.internal.concurrent.StoppableExecutorImpl$1.run(StoppableExecutorImpl.java:40)
at org.gradle.tooling.internal.consumer.BlockingResultHandler.getResult(BlockingResultHandler.java:46)
at org.gradle.tooling.internal.consumer.DefaultBuildLauncher.run(DefaultBuildLauncher.java:77)
at org.grails.cli.gradle.GradleUtil$_runBuildWithConsoleOutput_closure3.doCall(GradleUtil.groovy:97)
at org.grails.cli.gradle.GradleUtil$_withProjectConnection_closure1.doCall(GradleUtil.groovy:78)
at org.grails.cli.gradle.GradleUtil$_withProjectConnection_closure1.call(GradleUtil.groovy)
at grails.io.support.SystemOutErrCapturer.withNullOutput(SystemOutErrCapturer.groovy:64)
at org.grails.cli.gradle.GradleUtil.withProjectConnection(GradleUtil.groovy:77)
at org.grails.cli.gradle.GradleUtil.runBuildWithConsoleOutput(GradleUtil.groovy:92)
at org.grails.cli.gradle.GradleInvoker.invokeMethod(GradleInvoker.groovy:50)
at org.grails.cli.gradle.GradleAsyncInvoker$_invokeMethod_closure2.doCall(GradleAsyncInvoker.groovy:57)
at org.grails.cli.gradle.GradleAsyncInvoker$_invokeMethod_closure2.doCall(GradleAsyncInvoker.groovy)
Caused by: org.gradle.internal.exceptions.LocationAwareException: Cannot infer Groovy class path because no Groovy Jar was found on class path: file collection
Caused by: org.gradle.api.GradleException: Cannot infer Groovy class path because no Groovy Jar was found on class path: file collection
App build.gradle:
grails {
exploded = true
plugins{
compile project(":../plugin1")
}
}
App settings.gradle:
rootProject.name = 'grailsapp'
include 'grailsapp', '../plugin1'
project(':grailsapp').name = 'grailsapp'
Plugin1 build.gradle
grails {
exploded = true
plugins{
compile project(":../plugin2")
}
}
Plugin1 settings.gradle
rootProject.name = 'plugin1'
include 'plugin1', '../plugin2'
project(':plugin1').name = 'plugin1'
Я не понимаю, почему система не может найти Groovy.Используемая IDE - это IntelliJ IDEA.Может ли кто-нибудь дать мне совет, что попробовать?Спасибо!