with account as
(
select 'client1' as client, to_date('09.2009' ,'MM.YYYY') as months, '09_1' as bill_num, 100 as BF_sum, 400 as Payed_SUM from dual
union
select 'client1' as client, to_date('09.2009' ,'MM.YYYY') as months, '09_2' as bill_num, 150 as BF_sum, 50 as Payed_SUM from dual
union
select 'client1' as client, to_date('10.2009' ,'MM.YYYY') as months, '10_1' as bill_num, 150 as BF_sum, 50 as Payed_SUM from dual
union
select 'client1' as client, to_date('11.2009' ,'MM.YYYY') as months, '11_1' as bill_num, 150 as BF_sum, 0 as Payed_SUM from dual
union
select 'client1' as client, to_date('12.2009' ,'MM.YYYY') as months, '12_1' as bill_num, 150 as BF_sum, 100 as Payed_SUM from dual
)
select client, months, BF_sum, Payed_SUM, KREDIT, KREDIT+lag( KREDIT,1, 0 ) over (partition by client order by months) as lead_val
from (
select client, months, sum(BF_sum) as BF_sum, sum(Payed_SUM) as Payed_SUM, ( sum(Payed_SUM) - sum(BF_sum)) as KREDIT
from account
group by client, months
)
order by client, months
Как видите, при использовании функции LAG я получил следующее:
CLIENT MONTHS BF_SUM PAYED_SUM KREDIT LEAD_VAL
client1 01.09.2009 0:00:00 250 450 200 200
client1 01.10.2009 0:00:00 150 50 -100 100
client1 01.11.2009 0:00:00 150 0 -150 -250
client1 01.12.2009 0:00:00 150 100 -50 -200
И мне нужно использовать SUM от 09.2009 (Kredit = 200) для оплаты счетов за 10.2009 и других счетов, если деньги еще остались.
поэтому я хотел бы получить результат:
client months BF_SUM PAYED_SUM KREDIT NEW_KREDIT_MONTHS
client1 '09.2009' 250 450 200 0
client1 '10.2009' 150 50 -100 0
client1 '11.2009' 150 0 -150 -50
client1 '12.2009' 150 100 -50 -50
Возможно, мне нужно подключиться к «циклу» через все неоплаченные суммы, пока кредит не закончится ???
Есть мысли, ребята?