Как получить строку, которая содержит определенную строку между двумя точками остановки

Question

В случае, если это слишком запутанно, позвольте мне привести вам пример для лучшего понимания.

DECLARE @HotelDes varchar(1000) = 'Wake up to breathtaking views of the iconic Sydney Opera House, the Harbour Bridge or Darling Harbour each morning. You will be spoiled for choice at the Shangri-La Hotel, with a day spa, fitness centre and indoor pool at your disposal. The Shangri-la Sydney is located in the historic Rocks area, where Europeans first settled in Australia in 1788. This enviable location is just 5 minutes’ walk from both the Sydney Opera House and the MCA (Museum of Contemporary Art). After a day of sightseeing, you can relax in the bathtub of your lavish marble bathroom. All rooms include free Wi-Fi and an iPod dock, as well as fluffy bathrobes and slippers. CHI, The Spa offers a luxurious escape in its private spa suites, with a range of body treatments and massages on offer. The hotel also offers a hot tub, sauna and sun deck so you can make the most of your stay. The award-winning Altitude Restaurant boasts magnificent views of the harbour. Café Mix offers international all-day dining, while the New York-inspired Blu Bar on 36 is the perfect spot for a creative cocktail.';
DECLARE @HotelCat varchar(200) = 'sauna';

так что мне нужна строка, которая содержит слово "сауна" и эта строка будет между двумя точками остановки.

Я хочу, чтобы текст показывал: "В отеле также есть гидромассажная ванна, сауна и солярий, чтобы вы могли максимально использовать свое пребывание" между двумя полными остановками.

Я пробовал:

SELECT SUBSTRING(@HotelDes,CHARINDEX('.',@HotelDes)+1, CHARINDEX('.',@HotelDes,CHARINDEX('.',@HotelDes)+1) -CHARINDEX('.',@HotelDes)-1) 

Возвращает строку «Вы будете избалованы выбором в отеле Shangri-La с дневным спа-салоном, фитнес-центром и крытым бассейном» с первой полной остановки.

Кто-нибудь имеет представление о том, как получить строку с текстом "сауна"?

Answer 1

Вот другой подход.

DECLARE @HotelDes varchar(max) = 'Wake up to breathtaking views of the iconic Sydney Opera House, the Harbour Bridge or Darling Harbour each morning. You will be spoiled for choice at the Shangri-La Hotel, with a day spa, fitness centre and indoor pool at your disposal. The Shangri-la Sydney is located in the historic Rocks area, where Europeans first settled in Australia in 1788. This enviable location is just 5 minutes’ walk from both the Sydney Opera House and the MCA (Museum of Contemporary Art). After a day of sightseeing, you can relax in the bathtub of your lavish marble bathroom. All rooms include free Wi-Fi and an iPod dock, as well as fluffy bathrobes and slippers. CHI, The Spa offers a luxurious escape in its private spa suites, with a range of body treatments and massages on offer. The hotel also offers a hot tub, sauna and sun deck so you can make the most of your stay. The award-winning Altitude Restaurant boasts magnificent views of the harbour. Café Mix offers international all-day dining, while the New York-inspired Blu Bar on 36 is the perfect spot for a creative cocktail.';
DECLARE @HotelCat varchar(200) = 'sauna';


declare @s int,@e int, @cString varchar(max), @bString varchar(max), @fString varchar(max)
set @s=1
set @e= charindex('.',@HotelDes,@s)
set  @cString=SUBSTRING(@HotelDes,@s,@e)
set @bString =SUBSTRING(@HotelDes,@e+1,1000)



while @e>1

begin

if charindex(@HotelCat,@cString,1)>0 
set @fString=@cString

set @s = 1
set @e = charindex('.',@bString,@s)
set @cString = SUBSTRING(@bString,@s,@e)
set @bString = SUBSTRING(@bString,@e+1,1000)

end

select @fString

Answer 2

Для этого вам нужно создать табличную функцию разбиения строки.

CREATE FUNCTION [dbo].[fnSplitString] 
( 
    @string NVARCHAR(MAX), 
    @delimiter CHAR(1) 
) 
RETURNS @output TABLE(splitdata NVARCHAR(MAX) 
) 
BEGIN 
    DECLARE @start INT, @end INT 
    SELECT @start = 1, @end = CHARINDEX(@delimiter, @string) 
    WHILE @start < LEN(@string) + 1 BEGIN 
        IF @end = 0  
            SET @end = LEN(@string) + 1

        INSERT INTO @output (splitdata)  
        VALUES(SUBSTRING(@string, @start, @end - @start)) 
        SET @start = @end + 1 
        SET @end = CHARINDEX(@delimiter, @string, @start)

    END 
    RETURN 
END


DECLARE @HotelDes varchar(1000) = 'Wake up to breathtaking views of the iconic Sydney Opera House, the Harbour Bridge or Darling Harbour each morning. You will be spoiled for choice at the Shangri-La Hotel, with a day spa, fitness centre and indoor pool at your disposal. The Shangri-la Sydney is located in the historic Rocks area, where Europeans first settled in Australia in 1788. This enviable location is just 5 minutes’ walk from both the Sydney Opera House and the MCA (Museum of Contemporary Art). After a day of sightseeing, you can relax in the bathtub of your lavish marble bathroom. All rooms include free Wi-Fi and an iPod dock, as well as fluffy bathrobes and slippers. CHI, The Spa offers a luxurious escape in its private spa suites, with a range of body treatments and massages on offer. The hotel also offers a hot tub, sauna and sun deck so you can make the most of your stay. The award-winning Altitude Restaurant boasts magnificent views of the harbour. Café Mix offers international all-day dining, while the New York-inspired Blu Bar on 36 is the perfect spot for a creative cocktail.';
DECLARE @HotelCat varchar(200) = 'sauna';


select splitdata+'.' from [dbo].[fnSplitString] (@HotelDes,'.')
where splitdata like '%'+@HotelCat+'%'

--Output
/*
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
 The hotel also offers a hot tub, sauna and sun deck so you can make the most of your stay.
*/

Answer 3

другим вариантом было бы использовать обратную строку и charindex, если у вас есть недружественные символы xml для перекрестного решения

with cte
  as (select 'Wake up to breathtaking views of the iconic Sydney Opera House, the Harbour Bridge or Darling Harbour each morning. You will be spoiled for choice at the Shangri-La Hotel, with a day spa, fitness centre and indoor pool at your disposal. The Shangri-la Sydney is located in the historic Rocks area, where Europeans first settled in Australia in 1788. This enviable location is just 5 minutes’ walk from both the Sydney Opera House and the MCA (Museum of Contemporary Art). After a day of sightseeing, you can relax in the bathtub of your lavish marble bathroom. All rooms include free Wi-Fi and an iPod dock, as well as fluffy bathrobes and slippers. CHI, The Spa offers a luxurious escape in its private spa suites, with a range of body treatments and massages on offer. The hotel also offers a hot tub, sauna and sun deck so you can make the most of your stay. The award-winning Altitude Restaurant boasts magnificent views of the harbour. Café Mix offers international all-day dining, while the New York-inspired Blu Bar on 36 is the perfect spot for a creative cocktail.' as sentence
              ,'sauna' as  search_str
      )
select --charindex(search_str,sentence)
       --,charindex('.',sentence,charindex(search_str,sentence)+1)
       --,substring(sentence,1,charindex('.',sentence,charindex(search_str,sentence)+1)-1)
       --reverse(substring(sentence,1,charindex('.',sentence,charindex(search_str,sentence)+1)-1))
       --,charindex('.',reverse(substring(sentence,1,charindex('.',sentence,charindex(search_str,sentence)+1)-1)))
       reverse(
               substring(
                reverse(substring(sentence,1,charindex('.',sentence,charindex(search_str,sentence)+1)-1))
                ,1
                ,charindex('.',reverse(substring(sentence,1,charindex('.',sentence,charindex(search_str,sentence)+1)-1)))-1
                )
               ) as col3
  from cte

Db Fiddle link

https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=66d0a45fe0dac0c6ddacff421d341ed1

Answer 4

SELECT [DATA]
FROM(
    SELECT Split.a.value('.', 'NVARCHAR(MAX)') DATA
    FROM
    (
        SELECT CAST('<X>'+REPLACE(@HotelDes, '.', '</X><X>')+'</X>' AS XML) AS String
    ) AS A
    CROSS APPLY String.nodes('/X') AS Split(a)) as q
WHERE [data] LIKE '%sauna%';