Использование кода из Возможно ли перебирать аргументы в вариационных макросах?, вы можете сделать (жестко закодировано до 8 аргументов):
#define CONCATENATE(arg1, arg2) CONCATENATE1(arg1, arg2)
#define CONCATENATE1(arg1, arg2) CONCATENATE2(arg1, arg2)
#define CONCATENATE2(arg1, arg2) arg1##arg2
#define FOR_EACH_1(what, x) what(x);
#define FOR_EACH_2(what, x, ...)\
what(x);\
FOR_EACH_1(what, __VA_ARGS__)
#define FOR_EACH_3(what, x, ...)\
what(x);\
FOR_EACH_2(what, __VA_ARGS__)
#define FOR_EACH_4(what, x, ...)\
what(x);\
FOR_EACH_3(what, __VA_ARGS__)
#define FOR_EACH_5(what, x, ...)\
what(x);\
FOR_EACH_4(what, __VA_ARGS__)
#define FOR_EACH_6(what, x, ...)\
what(x);\
FOR_EACH_5(what, __VA_ARGS__)
#define FOR_EACH_7(what, x, ...)\
what(x);\
FOR_EACH_6(what, __VA_ARGS__)
#define FOR_EACH_8(what, x, ...)\
what(x);\
FOR_EACH_7(what, __VA_ARGS__)
#define FOR_EACH_NARG(...) FOR_EACH_NARG_(__VA_ARGS__, FOR_EACH_RSEQ_N())
#define FOR_EACH_NARG_(...) FOR_EACH_ARG_N(__VA_ARGS__)
#define FOR_EACH_ARG_N(_1, _2, _3, _4, _5, _6, _7, _8, N, ...) N
#define FOR_EACH_RSEQ_N() 8, 7, 6, 5, 4, 3, 2, 1, 0
#define FOR_EACH_(N, what, ...) CONCATENATE(FOR_EACH_, N)(what, __VA_ARGS__)
#define FOR_EACH(what, ...) FOR_EACH_(FOR_EACH_NARG(__VA_ARGS__), what, __VA_ARGS__)
#define STRING_MEMBERS(x) std::string x
#define CREATE_STRUCT(name, ...) struct name { FOR_EACH(STRING_MEMBERS, __VA_ARGS__) }
CREATE_STRUCT(my_struct1, foo);
CREATE_STRUCT(my_struct2,foo,bar);