уверен,
def my_function(value1, value2, value3, args=(0,0)):
print(value1, value2, value3, args)
# call with only 3 values
# it will use args=(0,0) as default
my_function(1,2,3)
# call with 3 values and args
my_function(4,5,6, args=(7,8))
вывод:
1 2 3 (0, 0)
4 5 6 (7, 8)