имя питона - PullRequest
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имя питона

0 голосов
/ 28 октября 2018
x = df2.Tweet
y = df2.Class
from sklearn.cross_validation import train_test_split
SEED = 2000
x_train, x_validation_and_test, y_train, y_validation_and_test = train_test_split(x, y, test_size=.02, random_state=SEED)
x_validation, x_test, y_validation, y_test = train_test_split(x_validation_and_test, y_validation_and_test, test_size=.5, random_state=SEED)
print ("Train set has total {0} entries with {1:.2f}% negative, {2:.2f}% positive".format(len(x_train),(len(x_train[y_train == 0])/ (len(x_train)*1.))*100,(len(x_train[y_train == 1]) / (len(x_train)*1.))*100))

print("Validation set has total {0} entries with {1:.2f}% negative, {2:.2f}% positive".format(len(x_validation),(len(x_validation[y_validation == 0]) / (len(x_validation)*1.))*100,(len(x_validation[y_validation == 1]) / (len(x_validation)*1.))*100))
print ("Test set has total {0} entries with {1:.2f}% negative,{2:.2f}% positive".format(len(x_test),(len(x_test[y_test == 0]) / (len(x_test)*1.))*100,(len(x_test[y_test == 1]) / (len(x_test)*1.))*100))

Я разделил свои данные на обучающие и тестовые наборы, используя приведенный выше код.

from sklearn.feature_extraction.text import CountVectorizer
from sklearn.linear_model import LogisticRegression
from sklearn.pipeline import Pipeline
from time import time


def accuracy_summary(pipeline, x_train, y_train, x_test, y_test):
    if len(x_test[y_test == 0]) / (len(x_test)*1.) > 0.5:
        null_accuracy = len(x_test[y_test == 0]) / (len(x_test)*1.)
    else:
        null_accuracy = 1. - (len(x_test[y_test == 0]) / (len(x_test)*1.))
    t0 = time()
    sentiment_fit = pipeline.fit(x_train, y_train)
    y_pred = sentiment_fit.predict(x_test)
    train_test_time = time() - t0
    accuracy = accuracy_score(y_test, y_pred)
    print("null accuracy: {0:.2f}%".format(null_accuracy*100))
    print("accuracy score: {0:.2f}%".format(accuracy*100))
    if accuracy > null_accuracy:
        print("model is {0:.2f}% more accurate than null accuracy".format((accuracy-null_accuracy)*100))
    elif accuracy == null_accuracy:
        print("model has the same accuracy with the null accuracy")
    else:
        print("model is {0:.2f}% less accurate than null accuracy".format((null_accuracy-accuracy)*100))
    print("train and test time: {0:.2f}s".format(train_test_time))
    print ("-"*80)
    return accuracy, train_test_time
cvec = CountVectorizer()
lr = LogisticRegression()
n_features = np.arange(10000,100001,10000)
def nfeature_accuracy_checker(vectorizer=cvec, n_features=n_features, stop_words=None, ngram_range=(1, 1), classifier=lr):
    result = []
    print (classifier)
    print("\n")
    for n in n_features:
        vectorizer.set_params(stop_words=stop_words, max_features=n, ngram_range=ngram_range)
        checker_pipeline = Pipeline([
            ('vectorizer', vectorizer),
            ('classifier', classifier)
        ])
        print("Validation result for {} features".format(n))
        nfeature_accuracy,tt_time = accuracy_summary(checker_pipeline, x_train, y_train, x_validation, y_validation)
        result.append((n,nfeature_accuracy,tt_time))
    return result

Я определил вышеупомянутую функцию для выполнения логистической регрессии на моих данных твитов.При запуске кода ниже я получаю «NameError: имя точность_score не определена».Я преобразовал свои данные класса (0 и 1) в тип int, но я все еще получаю эту ошибку.

Код вызова функции

print("RESULT FOR UNIGRAM WITHOUT STOP WORDS\n")
feature_result_wosw = nfeature_accuracy_checker(stop_words='english')

Импортировал мой CSV, используя этот код

cols = ['Tweet','Class']
df = pd.read_csv("data.csv",header = None,names = cols,converters={"CLASS":int})
df.head()

enter image description here

1 Ответ

0 голосов
/ 28 октября 2018

Вы не импортировали функцию оценки точности

from sklearn.metrics import accuracy_score
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