COALESCE с суммой с таблицей соединений неверен - PullRequest
0 голосов
/ 17 мая 2018

Я работаю над таблицей соединений с объединением 5 различных таблиц вместе. Я написал код для объединения всех таблиц, и он прекрасно работает без таблицы объединения

, как вы видите код

    SELECT  sku,
        sum(units_ordered) as units_ordered
FROM   (
        SELECT sku, units_ordered
        FROM   tbl_sku_units_order 
        UNION ALL
        SELECT sku, units_ordered
        FROM   tbl_sku_units_order_de
        UNION ALL
        SELECT sku, units_ordered
        FROM   tbl_sku_units_order_es
        UNION ALL
        SELECT sku, units_ordered
        FROM   tbl_sku_units_order_fr
        UNION ALL
        SELECT sku, units_ordered
        FROM   tbl_sku_units_order_it
       ) AllMarketplace
group by sku
ORDER BY units_ordered DESC;

, как вы видите результат в первой ссылке на db fiddle

https://www.db -fiddle.com / f / nbGcxACaf4doHRssJDSyRN / 0 и результат правильный

enter image description here

Вы можете увидеть «H-Root-M012S-Black 87», который является правильным в общем количестве QTY.

Мне нужно, чтобы они присоединились к одной из других таблиц как левое соединение.Вот код в db fiddle

https://www.db -fiddle.com / f / dxqsU4enjRYqk7du7VEB4d / 0

это код, который я написал

SELECT 
    ls.sku                                  AS list_sku,
    COALESCE(MIN(suo.sku), 'Not Sold')      AS sold_sku,
    COALESCE(SUM(suo.units_ordered), 0)     AS units_ordered
FROM
    (SELECT 
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order 
        UNION ALL
        SELECT  
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_de
        UNION ALL
        SELECT 
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_es
        UNION ALL
        SELECT 
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_fr
        UNION ALL
        SELECT  
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_it
    ) as t1,
    tbl_list_sku AS ls
        LEFT JOIN
    tbl_sku_units_order AS suo ON suo.sku = ls.sku
GROUP BY ls.sku
ORDER BY units_ordered DESC;

И он возвращается нормально, но расчет неверен

enter image description here

Я подозреваю, что это из-за групповой проблемы?Я должен настроить его на группу, но все результаты дали одинаковые результаты вместе с правыми или внутренними таблицами соединения.

1 Ответ

0 голосов
/ 17 мая 2018

Ваш SQL должен быть таким:

SELECT 
    ls.sku                                  AS list_sku,
    COALESCE(MIN(suo.sku), 'Not Sold')      AS sold_sku,
    COALESCE(SUM(suo.units_ordered), 0)     AS units_ordered
FROM
    (SELECT sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order 
        UNION ALL
        SELECT sku,  
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_de
        UNION ALL
        SELECT sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_es
        UNION ALL
        SELECT sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_fr
        UNION ALL
        SELECT  sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_it
    ) as t1 join 
    tbl_list_sku AS ls on t1.sku = ls.sku
        LEFT JOIN
    tbl_sku_units_order AS suo ON suo.sku = ls.sku
GROUP BY ls.sku
ORDER BY units_ordered DESC;

EDIT-1

SELECT 
    ls.sku                                  AS list_sku,
    COALESCE(MIN(suo.sku), 'Not Sold')      AS sold_sku,
    COALESCE(SUM(suo.units_ordered), 0)     AS units_ordered
FROM tbl_list_sku AS ls left join
    (SELECT sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order 
        UNION ALL
        SELECT sku,  
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_de
        UNION ALL
        SELECT sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_es
        UNION ALL
        SELECT sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_fr
        UNION ALL
        SELECT  sku,
        COALESCE(MIN(sku), 'Not Sold')      AS sold_sku,
        COALESCE(SUM(units_ordered), 0)     AS units_ordered
        FROM   tbl_sku_units_order_it
    ) as t1 on t1.sku = ls.sku
        LEFT JOIN
    tbl_sku_units_order AS suo ON suo.sku = ls.sku
GROUP BY ls.sku
ORDER BY units_ordered DESC;
...