Ошибка сегментации: 11 - Xcode 10

Question

2. Во время проверки типа в RangeText = "{ playlistNames = [] let requestLibrary = NSFetchRequest (entityName: "Library")

   let request = NSFetchRequest<NSFetchRequestResult>(entityName: "Playlist")
   request.sortDescriptors = [playlistSortDescriptor]
   
   playlists = try? context.fetch(request) as NSArray!
   print("Playlist Count - ",playlists.count)
   
   
   let librarys:NSArray! = try? context.fetch(requestLibrary) as NSArray!
   for library in librarys{
       let libraryName = (library as AnyObject).value(forKey: "library") as! String
       playlistNames += [libraryName]
   }
   
   for playlist in playlists{
       let playlistName = (playlist as AnyObject).value(forKey: "playlistName") as! String
       if playlistName == "Library" {
           playlistNames.insert(playlistName, at: 0)
       }else {
           playlistNames += [playlistName]
       }
   }
   

   } "

3. При проверке типа выражения в RangeText = "playlists = try? Context.fetch (request) as NSArray!" ошибка: ошибка сегментации: 11

Вот код:

 func refreshPlaylists(){
    playlistNames = []
    let requestLibrary = NSFetchRequest<NSFetchRequestResult>(entityName: "Library")

    let request = NSFetchRequest<NSFetchRequestResult>(entityName: "Playlist")
    request.sortDescriptors = [playlistSortDescriptor]

    playlists = try? context.fetch(request) as NSArray!
    print("Playlist Count - ",playlists.count)


    let librarys:NSArray! = try? context.fetch(requestLibrary) as NSArray!
    for library in librarys{
        let libraryName = (library as AnyObject).value(forKey: "library") as! String
        playlistNames += [libraryName]
    }

    for playlist in playlists{
        let playlistName = (playlist as AnyObject).value(forKey: "playlistName") as! String
        if playlistName == "Library" {
            playlistNames.insert(playlistName, at: 0)
        }else {
            playlistNames += [playlistName]
        }
    }
}

Это работает до того, как я обновлюсь до Xcode 10. Есть идеи?

Answer 1

Нет такого типа, как NSArray!, и ни в коем случае у вас никогда не было причин использовать его.Удалить as NSArray! во всем.Используйте типы Swift.