Проверьте это. Выражение предиката XPath проверяет наличие всех трех обязательных атрибутов: C, D и F.
SQL
-- DDL and sample data population, start
DECLARE @tbl TABLE (term_uid VARCHAR(50) PRIMARY KEY, xmldata XML);
INSERT INTO @tbl (term_uid, xmldata)
VALUES
('7D54155E-75E8-4BBC-9112-0002C70FC781',
N'<Attributes>
<server.context.tablName term_uid="7D54155E-75E8-4BBC-9112-0002C70FC781" field1="I71.0">
<Attributes xmlns="">
<Attribute name="A">3</Attribute>
<Attribute name="B">HHS_HCC154</Attribute>
<Attribute name="C">I71.0</Attribute>
<Attribute name="D">I71.00</Attribute>
<Attribute name="F">308546005</Attribute>
</Attributes>
</server.context.tablName>
<server.context.tablName term_uid="1C572AF2-CD26-4C41-B449-0004FF5F4E6E" field1="">
<Attributes xmlns="">
<Attribute name="A">2131</Attribute>
<Attribute name="F">20013001</Attribute>
</Attributes>
</server.context.tablName>
<server.context.tablName term_uid="744A553A-0C2A-4FD7-8004-000519EFAC75" field1="">
<Attributes xmlns="">
<Attribute name="D">H66.001</Attribute>
<Attribute name="F">14948001</Attribute>
</Attributes>
</server.context.tablName>
<server.context.tablName term_uid="5E70C463-4489-4DA7-B410-00082E8E68C5" field1="">
<Attributes xmlns="">
<Attribute name="D">S62.353S</Attribute>
<Attribute name="F">704024008</Attribute>
</Attributes>
</server.context.tablName>
<server.context.tablName term_uid="EEDBCC0B-75B9-47D9-8E7A-000A4B604135" field1="R97.2">
<Attributes xmlns="">
<Attribute name="A">3</Attribute>
<Attribute name="C">R97.2</Attribute>
<Attribute name="D">790.93</Attribute>
<Attribute name="F">396152005</Attribute>
</Attributes>
</server.context.tablName>
</Attributes>');
-- DDL and sample data population, end
SELECT term_uid
, p.value('@term_uid','VARCHAR(50)') AS term
, c.value('(Attribute[@name="C"]/text())[1]','VARCHAR(10)') AS c
, c.value('(Attribute[@name="D"]/text())[1]','VARCHAR(10)') AS d
, c.value('(Attribute[@name="F"]/text())[1]','VARCHAR(10)') AS f
FROM @tbl AS tbl
CROSS APPLY tbl.xmldata.nodes('/Attributes/server.context.tablName') AS parent(p)
CROSS APPLY p.nodes('Attributes[Attribute[@name="C"]
and Attribute[@name="D"]
and Attribute[@name="F"]]') AS child(c);
Вывод
+--------------------------------------+--------------------------------------+-------+--------+-----------+
| term_uid | term | c | d | f |
+--------------------------------------+--------------------------------------+-------+--------+-----------+
| 7D54155E-75E8-4BBC-9112-0002C70FC781 | 7D54155E-75E8-4BBC-9112-0002C70FC781 | I71.0 | I71.00 | 308546005 |
| 7D54155E-75E8-4BBC-9112-0002C70FC781 | EEDBCC0B-75B9-47D9-8E7A-000A4B604135 | R97.2 | 790.93 | 396152005 |
+--------------------------------------+--------------------------------------+-------+--------+-----------+