У меня есть следующее демо
CREATE TABLE `tblappointment` (
`app_id` mediumint(8) UNSIGNED NOT NULL,
`app_date` date NOT NULL,
`work_id` smallint(5) UNSIGNED NOT NULL,
`app_price` double DEFAULT NULL,
`app_price_paid` double DEFAULT NULL,
`receipt_id` tinyint(3) UNSIGNED DEFAULT NULL
);
INSERT INTO `tblappointment` (`app_id`, `app_date`, `work_id`, `app_price`, `app_price_paid`, `receipt_id`) VALUES
("1", "2020-03-01", "21", "100", "50", "1"),
("2", "2020-04-01", "21", "200", "40", "3"),
("4", "2020-06-01", "2", "500", "70", "1"),
("5", "2020-07-01", "21", "300", "30", "1"),
("6", "2020-08-01", "21", "200", "20", "2"),
("7", "2020-09-01", "5", "100", "50", "1"),
("8", "2020-10-01", "6", "200", "30", "2"),
("9", "2020-11-01", "21", "300", "30", "1"),
("10", "2020-12-01", "21", "400", "20", "3"),
("11", "2020-01-01", "8", "500", "90", "1"),
("12", "2020-02-01", "21", "600", "80", "5"),
("13", "2020-03-01", "3", "700", "70", "1");
Пример кода и схемы
sql:
SELECT
YEAR(app_date) AS aYear,
Month(app_date) AS aMonth,
SUM(CASE WHEN work_id = 21 THEN app_price END) AS Work,
SUM(CASE WHEN work_id = 21 THEN app_price_paid END) AS Paid,
SUM(CASE WHEN work_id = 21 THEN app_price END)-SUM(CASE WHEN work_id = 21 THEN app_price_paid END) AS Debt
FROM tblappointment
GROUP BY YEAR(app_date), Month(app_date)
ORDER BY YEAR(app_date), Month(app_date);
Вывод сейчас:
YEAR MONTH WORK PAID DEBT
2020 1 numbers here...
2020 2 numbers here...
Я хотел бы получить такой вывод:
YEAR DETAILS 1 2 3 4 5 6 7 8 9 10 11 12
2020 Work numbers here....
2020 Paid numbers here....
2020 Debt numbers here....
Спасибо