Почему Entity Framework (с RIA Services) исключает родительские записи, когда дочерние записи не существуют? - PullRequest
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Почему Entity Framework (с RIA Services) исключает родительские записи, когда дочерние записи не существуют?

0 голосов
/ 18 марта 2012

Entity Framework 4 исключает записи, которые, по моему мнению, не должны быть. Вот мой сценарий:

Таблица определений 

Table_1

    UniqueIdentifier ID not null
    int AnotherField

Table_2

    UniqueIdentifier ID not null
    UniqueIdentifier Table_1ID not null
    int Priority not null

Существует связь между таблицей 1 и таблицей 2 через поле table_1ID. Он определен в базе данных, и структура сущностей распознает его.

У меня есть запрос, определенный в моем DomainService как: 

private ObjectQuery<Table_1> Table_1WithIncludes()    
{        
    return this.ObjectContext.Table_1        
        .Include("Table_2")                
}

Если у меня есть записи в таблице 1 и таблице 2, которые связаны, они возвращаются, как ожидалось. Если у меня нет записи в таблице 2, относящейся к таблице 1, эта запись исключается.

После запуска SQL Server Profiler я заметил, что платформа сущностей добавила следующие CAST и предложения where: 

CASE WHEN ([Join2].[Priority] IS NULL) THEN CAST(NULL AS int) ELSE 1 END AS [C1]

WHERE ([Project1].[C1] > 0)

По сути, если поле Приоритет в Таблице_2 имеет значение NULL (что происходит, когда в Таблице 2 нет записи, соответствующей родительской таблице Tabe_1), условие where приводит к выпадению обеих записей (null> 0 не выполняется ).

Теперь, если я изменю определение поля «Приоритет», чтобы оно не требовалось, оно исключает приведение и проверку, и все в порядке. Но, похоже, мне не следует это делать.

Я сделал что-то не так? Мое понимание неверно?

Полный текст EntityQuery и сгенерированный текст запроса приведены ниже на случай, если это будет полезно. 

    private ObjectQuery<Event> EventsWithIncludes()
    {
        return this.ObjectContext.Events
            .Include("Place")
            .Include("EventInvitees")
            .Include("EventInvitees.User");
    }


exec sp_executesql N'SELECT 
[Project2].[NumberOfPeople] AS [NumberOfPeople], 
[Project2].[ID] AS [ID], 
[Project2].[CreatorID] AS [CreatorID], 
[Project2].[CreateDate] AS [CreateDate], 
[Project2].[PlacesID] AS [PlacesID], 
[Project2].[EventDate] AS [EventDate], 
[Project2].[EventTime] AS [EventTime], 
[Project2].[Availability] AS [Availability], 
[Project2].[EscalationLevels] AS [EscalationLevels], 
[Project2].[Rank] AS [Rank], 
[Project2].[RowVersion] AS [RowVersion], 
[Project2].[ID1] AS [ID1], 
[Project2].[Name] AS [Name], 
[Project2].[Phone] AS [Phone], 
[Project2].[DefaultPar] AS [DefaultPar], 
[Project2].[DefaultSlope] AS [DefaultSlope], 
[Project2].[DefaultRating] AS [DefaultRating], 
[Project2].[CreateDate1] AS [CreateDate1], 
[Project2].[UpdateDate] AS [UpdateDate], 
[Project2].[MetroAreaID] AS [MetroAreaID], 
[Project2].[C1] AS [C1], 
[Project2].[PriorityOrder] AS [PriorityOrder], 
[Project2].[ID2] AS [ID2], 
[Project2].[EventsID] AS [EventsID], 
[Project2].[InviteeUsersID] AS [InviteeUsersID], 
[Project2].[RowVersion1] AS [RowVersion1], 
[Project2].[Attending] AS [Attending], 
[Project2].[StatusChange] AS [StatusChange], 
[Project2].[ID3] AS [ID3], 
[Project2].[First] AS [First], 
[Project2].[Last] AS [Last], 
[Project2].[UserName] AS [UserName], 
[Project2].[Password] AS [Password], 
[Project2].[Gender] AS [Gender], 
[Project2].[Email] AS [Email], 
[Project2].[Email_Sharing] AS [Email_Sharing], 
[Project2].[Email_Receive] AS [Email_Receive], 
[Project2].[Phone1] AS [Phone1], 
[Project2].[Phone_Sharing] AS [Phone_Sharing], 
[Project2].[Phone_Receive] AS [Phone_Receive], 
[Project2].[CreateDate2] AS [CreateDate2], 
[Project2].[UpdateDate1] AS [UpdateDate1]
FROM ( SELECT 
    [Project1].[ID] AS [ID], 
    [Project1].[CreatorID] AS [CreatorID], 
    [Project1].[CreateDate] AS [CreateDate], 
    [Project1].[NumberOfPeople] AS [NumberOfPeople], 
    [Project1].[PlacesID] AS [PlacesID], 
    [Project1].[EventDate] AS [EventDate], 
    [Project1].[Availability] AS [Availability], 
    [Project1].[EscalationLevels] AS [EscalationLevels], 
    [Project1].[Rank] AS [Rank], 
    [Project1].[RowVersion] AS [RowVersion], 
    [Project1].[EventTime] AS [EventTime], 
    [Extent3].[ID] AS [ID1], 
    [Extent3].[Name] AS [Name], 
    [Extent3].[Phone] AS [Phone], 
    [Extent3].[DefaultPar] AS [DefaultPar], 
    [Extent3].[DefaultSlope] AS [DefaultSlope], 
    [Extent3].[DefaultRating] AS [DefaultRating], 
    [Extent3].[CreateDate] AS [CreateDate1], 
    [Extent3].[UpdateDate] AS [UpdateDate], 
    [Extent3].[MetroAreaID] AS [MetroAreaID], 
    [Join2].[ID1] AS [ID2], 
    [Join2].[EventsID] AS [EventsID], 
    [Join2].[InviteeUsersID] AS [InviteeUsersID], 
    [Join2].[PriorityOrder] AS [PriorityOrder], 
    [Join2].[RowVersion] AS [RowVersion1], 
    [Join2].[Attending] AS [Attending], 
    [Join2].[StatusChange] AS [StatusChange], 
    [Join2].[ID2] AS [ID3], 
    [Join2].[First] AS [First], 
    [Join2].[Last] AS [Last], 
    [Join2].[UserName] AS [UserName], 
    [Join2].[Password] AS [Password], 
    [Join2].[Gender] AS [Gender], 
    [Join2].[Email] AS [Email], 
    [Join2].[Email_Sharing] AS [Email_Sharing], 
    [Join2].[Email_Receive] AS [Email_Receive], 
    [Join2].[Phone] AS [Phone1], 
    [Join2].[Phone_Sharing] AS [Phone_Sharing], 
    [Join2].[Phone_Receive] AS [Phone_Receive], 
    [Join2].[CreateDate] AS [CreateDate2], 
    [Join2].[UpdateDate] AS [UpdateDate1], 
    CASE WHEN ([Join2].[PriorityOrder] IS NULL) THEN CAST(NULL AS int) ELSE 1 END AS [C1]
    FROM    (SELECT 
        [Extent1].[ID] AS [ID], 
        [Extent1].[CreatorID] AS [CreatorID], 
        [Extent1].[CreateDate] AS [CreateDate], 
        [Extent1].[NumberOfPeople] AS [NumberOfPeople], 
        [Extent1].[PlacesID] AS [PlacesID], 
        [Extent1].[EventDate] AS [EventDate], 
        [Extent1].[Availability] AS [Availability], 
        [Extent1].[EscalationLevels] AS [EscalationLevels], 
        [Extent1].[Rank] AS [Rank], 
    [Extent1].[RowVersion] AS [RowVersion], 
    [Extent1].[EventTime] AS [EventTime], 
    (SELECT 
        COUNT(1) AS [A1]
        FROM [dbo].[EventInvitees] AS [Extent2]
        WHERE ([Extent1].[ID] = [Extent2].[EventsID]) AND ([Extent2].[InviteeUsersID] = @p__linq__2)) AS [C1]
    FROM [dbo].[Events] AS [Extent1] ) AS [Project1]
LEFT OUTER JOIN [dbo].[Places] AS [Extent3] ON [Project1].[PlacesID] = [Extent3].[ID]
LEFT OUTER JOIN  (SELECT [Extent4].[ID] AS [ID1], [Extent4].[EventsID] AS [EventsID], [Extent4].[InviteeUsersID] AS [InviteeUsersID], [Extent4].[PriorityOrder] AS [PriorityOrder], [Extent4].[RowVersion] AS [RowVersion], [Extent4].[Attending] AS [Attending], [Extent4].[StatusChange] AS [StatusChange], [Extent5].[ID] AS [ID2], [Extent5].[First] AS [First], [Extent5].[Last] AS [Last], [Extent5].[UserName] AS [UserName], [Extent5].[Password] AS [Password], [Extent5].[Gender] AS [Gender], [Extent5].[Email] AS [Email], [Extent5].[Email_Sharing] AS [Email_Sharing], [Extent5].[Email_Receive] AS [Email_Receive], [Extent5].[Phone] AS [Phone], [Extent5].[Phone_Sharing] AS [Phone_Sharing], [Extent5].[Phone_Receive] AS [Phone_Receive], [Extent5].[CreateDate] AS [CreateDate], [Extent5].[UpdateDate] AS [UpdateDate]
    FROM  [dbo].[EventInvitees] AS [Extent4]
    INNER JOIN [dbo].[Users] AS [Extent5] ON [Extent4].[InviteeUsersID] = [Extent5].[ID] ) AS [Join2] ON [Project1].[ID] = [Join2].[EventsID]
WHERE ([Project1].[C1] > 0) AND ([Project1].[CreatorID] = @p__linq__0) AND (([Project1].[EventDate] IS NULL) OR ([Project1].[EventDate] >= @p__linq__1))
)  AS [Project2]
ORDER BY [Project2].[ID] ASC, [Project2].[ID1] ASC, [Project2].[C1] ASC',N'@p__linq__2     uniqueidentifier,@p__linq__0 uniqueidentifier,@p__linq__1 datetime2(7)',@p__linq__2='33BB8199-7B25-4B3A-B96D-044EB7DB70AE',@p__linq__0='33BB8199-7B25-4B3A-B96D-044EB7DB70AE',@p__linq__1='1900-01-01 00:00:00'

Таблица определений 

USE [TheGreen18]
GO

/****** Object:  Table [dbo].[EventInvitees]    Script Date: 03/17/2012 22:27:16 ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE TABLE [dbo].[EventInvitees](
    [ID] [uniqueidentifier] NOT NULL,
    [EventsID] [uniqueidentifier] NOT NULL,
    [InviteeUsersID] [uniqueidentifier] NOT NULL,
    [PriorityOrder] [int] NOT NULL,
    [RowVersion] [timestamp] NULL,
    [Attending] [bit] NULL,
    [StatusChange] [datetime] NULL,
 CONSTRAINT [PK_EventInvitees] PRIMARY KEY CLUSTERED 
(
    [ID] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

ALTER TABLE [dbo].[EventInvitees]  WITH CHECK ADD  CONSTRAINT [FK_EventInvitees_Events] FOREIGN KEY([EventsID])
REFERENCES [dbo].[Events] ([ID])
ON DELETE CASCADE
GO

ALTER TABLE [dbo].[EventInvitees] CHECK CONSTRAINT [FK_EventInvitees_Events]
GO

ALTER TABLE [dbo].[EventInvitees]  WITH CHECK ADD  CONSTRAINT [FK_EventInvitees_Users] FOREIGN KEY([InviteeUsersID])
REFERENCES [dbo].[Users] ([ID])
GO

ALTER TABLE [dbo].[EventInvitees] CHECK CONSTRAINT [FK_EventInvitees_Users]
GO

Ответы [ 2 ]

0 голосов
/ 18 марта 2012

То, что я видел в Entity Framework, одиночный Include всегда переводится как внешнее соединение.Однако в случае нескольких включений порядок включений определяет, являются ли соединения внутренними или внешними.

В вашем примере я предполагаю, что «Place» - это внешнее соединение, тогда как «EventInvitees» и «User» - внутреннее.присоединился.(По крайней мере, это то, что происходит, когда я делаю аналогичный запрос).

Если вы измените порядок на 

.Include("EventInvitees")
.Include("EventInvitees.User")
.Include("Place")

, то "Place" будет внутренним соединением, а "EventInvitees" внешним соединением (опять же, исходя из моего аналогичного случая).

Я не могу найти никакой документации по точной логике этого на MSDN, поэтому ваш результат может отличаться от моего.

0 голосов
/ 18 марта 2012

Если ваш внешний ключ не имеет значения null, то, согласно EF, ваше отношение одно к многим, у каждого ребенка должен быть родитель.Таким образом, теоретически у вас не может быть ребенка без родителя.

Если вы хотите иметь ребенка без родителя, то ваше отношение равно нулю или от одного ко многим, и ваш внешний ключ должен быть нулевым.

...