Я использую Apache POI для чтения файла xlsx, он работает хорошо.У меня есть вопрос к вам, когда строка найдена нулевой, как я могу справиться с этим?Мой файл содержит 500 строк, но он показывает 105667 строк, остаток строки найден нулевым.
используемый код:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import java.text.SimpleDateFormat;
import java.util.logging.Level;
import java.util.logging.Logger;
import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.DateUtil;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.ss.usermodel.Sheet;
import org.apache.poi.ss.usermodel.Workbook;
import org.apache.poi.ss.usermodel.WorkbookFactory;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
/**
*
* @author SAMEEK
*/
public class readXLSXFile {
public int getNumberOfColumn(String fileName, int sheetIndex) throws FileNotFoundException, IOException {
File inputFile = null;
FileInputStream fis = null;
XSSFWorkbook workbook = null;
XSSFSheet sheet = null;
XSSFRow row = null;
int lastRowNum = 0;
int lastCellNum = 0;
// Open the workbook
inputFile = new File(fileName);
fis = new FileInputStream(inputFile);
workbook = new XSSFWorkbook(fis);
sheet = workbook.getSheetAt(sheetIndex);
lastRowNum = sheet.getLastRowNum();
for (int i = 0; i < lastRowNum; i++) {
row = sheet.getRow(i);
if (row != null) {
if (row.getLastCellNum() > lastCellNum) {
lastCellNum = row.getLastCellNum();
}
}
}
return lastCellNum;
}
public int getNumberOfRow(String fileName, int sheetIndex) throws FileNotFoundException, IOException {
File inputFile = null;
FileInputStream fis = null;
XSSFWorkbook workbook = null;
XSSFSheet sheet = null;
int lastRowNum = 0;
// Open the workbook
inputFile = new File(fileName);
fis = new FileInputStream(inputFile);
workbook = new XSSFWorkbook(fis);
sheet = workbook.getSheetAt(sheetIndex);
lastRowNum = sheet.getLastRowNum();
return lastRowNum;
}
public String[] getSheetName(String fileName) throws FileNotFoundException, IOException {
int totalsheet = 0;
int i = 0;
String[] sheetName = null;
File inputFile = null;
FileInputStream fis = null;
XSSFWorkbook workbook = null;
// Open the workbook
inputFile = new File(fileName);
fis = new FileInputStream(inputFile);
workbook = new XSSFWorkbook(fis);
totalsheet = workbook.getNumberOfSheets();
sheetName = new String[totalsheet];
while (i < totalsheet) {
sheetName[i] = workbook.getSheetName(i);
i++;
}
return sheetName;
}
public int getNumberOfSheet(String fileName) throws FileNotFoundException, IOException {
int totalsheet = 0;
File inputFile = null;
FileInputStream fis = null;
XSSFWorkbook workbook = null;
XSSFSheet sheet = null;
int lastRowNum = 0;
// Open the workbook
inputFile = new File(fileName);
fis = new FileInputStream(inputFile);
workbook = new XSSFWorkbook(fis);
totalsheet = workbook.getNumberOfSheets();
return totalsheet;
}
public String[][] getSheetData(String fileName, int sheetIndex) throws FileNotFoundException, IOException, InvalidFormatException {
String[][] data = null;
int i = 0;
int j = 0;Cell cell=null;
long emptyrowcount = 0;
InputStream inputStream = new FileInputStream(
fileName);
// Create a workbook object.
Workbook wb = WorkbookFactory.create(inputStream);
wb.setMissingCellPolicy(Row.CREATE_NULL_AS_BLANK);
Sheet sheet = wb.getSheetAt(sheetIndex);
// Iterate over all the row and cells
int noOfColumns = getNumberOfColumn(fileName, sheetIndex);
System.out.println("noOfColumns::" + noOfColumns);
int noOfRows = getNumberOfRow(fileName, sheetIndex) + 1;
System.out.println("noOfRows::" + noOfRows);
data = new String[noOfRows][noOfColumns];
for (int k = 0; k < noOfRows; k++) {
Row row = sheet.getRow(k);
if (row == null) {
} else {
j = 0;
for (int l = 0; l < noOfColumns; l++) {
// Cell cell = cit.next();
cell = row.getCell(j);
if (cell.getCellType() == cell.CELL_TYPE_BLANK) {
cell = row.getCell(j, Row.CREATE_NULL_AS_BLANK);
}
data[i][j] = getCellValueAsString(cell);
j++;
}
i++;
}
}
return data;
}
/**
* This method for the type of data in the cell, extracts the data and
* returns it as a string.
*/
public static String getCellValueAsString(Cell cell) {
String strCellValue = null;
if (cell != null) {
switch (cell.getCellType()) {
case Cell.CELL_TYPE_STRING:
strCellValue = cell.toString();
break;
case Cell.CELL_TYPE_NUMERIC:
if (DateUtil.isCellDateFormatted(cell)) {
SimpleDateFormat dateFormat = new SimpleDateFormat(
"dd/MM/yyyy");
strCellValue = dateFormat.format(cell.getDateCellValue());
} else {
Double value = cell.getNumericCellValue();
Long longValue = value.longValue();
strCellValue = new String(longValue.toString());
}
break;
case Cell.CELL_TYPE_BOOLEAN:
strCellValue = new String(new Boolean(
cell.getBooleanCellValue()).toString());
break;
case Cell.CELL_TYPE_BLANK:
strCellValue = "";
break;
}
}
return strCellValue;
}
public static void main(String s[]) {
try {
readXLSXFile readXLSxFile = new readXLSXFile();
String[][] sheetData = readXLSxFile.getSheetData("F:/work.xlsx", 0);
int columnLength = 0;
columnLength = readXLSxFile.getNumberOfColumn("F:/work.xlsx", 0);
int rowLength = 0;
rowLength = readXLSxFile.getNumberOfRow("F:/work.xlsx", 0);
int h = 0;
int j = 0;
while (j < rowLength) {
h = 0;
while (h < columnLength) {
System.out.print("\t " + sheetData[j][h]);
h++;
}
System.out.println("");
j++;
}
} catch (InvalidFormatException ex) {
Logger.getLogger(readXLSFile.class.getName()).log(Level.SEVERE, null, ex);
} catch (FileNotFoundException ex) {
Logger.getLogger(readXLSFile.class.getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
Logger.getLogger(readXLSFile.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
Пожалуйста, помогите мне, как обработать нулевую строку в листе Excel?