Мне нужно найти 95% доверительный интервал как 2,5 и 97,5 квантилей
boot_mean_diff = []
for i in range(3000):
boot_before = before_proportion
boot_after = after_proportion
boot_mean_diff.append(boot_after.mean()-boot_before.mean())
# Calculating a 95% confidence interval from boot_mean_diff
boot_mean_diff=pd.Series(boot_mean_diff)
#boot_mean_diff1=boot.boot_mean_diff(frac=1,replace=True)
confidence_interval = pd.Series(boot_mean_diff).quantile([0.025,0.975])
confidence_interval
Однако я получаю ошибку ниже ----
AssertionError: trust_intervalдолжен быть рассчитан как [0.025, 0.975] квантилей boot_mean_diff.