Apache poi WorkBookFactory.create (inputtream) создает исключение ZipException - PullRequest
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Apache poi WorkBookFactory.create (inputtream) создает исключение ZipException

0 голосов
/ 29 августа 2018

Это мой исходный код Java 

@Value("classpath:Metadata.xlsx")
    private Resource resource;

    public E2EMetadata readMetadata(E2ECommandContext commandContext) {
        E2EMetadata metadata = new E2EMetadata();
        try {
            Workbook metadataWorkbook = null;
            metadataWorkbook = WorkbookFactory.create(resource.getInputStream());
            List<OutputFileType> outputFileTypes = readOutputFilesMetadataSheet(metadataWorkbook);
            List<InputFileType> inputFileTypes = readInputFilesMetadataSheet(metadataWorkbook);
            metadata.setOutputFileTypes(outputFileTypes);
            metadata.setInputFileTypes(inputFileTypes);
            metadataWorkbook.close();
        } catch (Exception e) {
            throw new TestingToolsRuntimeException(e);
        }
        return metadata;
    }

Здесь, пока WorkbookFactory.create (resource.getInputStream ()) выдает исключение ZipException 

Caused by: java.io.IOException: Failed to read zip entry source
        at org.apache.poi.openxml4j.opc.ZipPackage.<init>(ZipPackage.java:103)
        at org.apache.poi.openxml4j.opc.OPCPackage.open(OPCPackage.java:324)
        at org.apache.poi.ss.usermodel.WorkbookFactory.create(WorkbookFactory.java:184)
        at org.apache.poi.ss.usermodel.WorkbookFactory.create(WorkbookFactory.java:149)
        at com.zafin.rpe.test.tools.MetadataReader.readMetadata(MetadataReader.java:36)
        ... 34 more
Caused by: java.util.zip.ZipException: invalid entry size (expected 1936483698 but got 1 bytes)
        at java.util.zip.ZipInputStream.readEnd(ZipInputStream.java:384)
        at java.util.zip.ZipInputStream.read(ZipInputStream.java:196)
        at org.apache.poi.openxml4j.util.ZipSecureFile$ThresholdInputStream.read(ZipSecureFile.java:220)
        at java.io.FilterInputStream.read(FilterInputStream.java:107)
        at org.apache.poi.openxml4j.util.ZipInputStreamZipEntrySource$FakeZipEntry.<init>(ZipInputStreamZipEntrySource.java:132)
        at org.apache.poi.openxml4j.util.ZipInputStreamZipEntrySource.<init>(ZipInputStreamZipEntrySource.java:56)
        at org.apache.poi.openxml4j.opc.ZipPackage.<init>(ZipPackage.java:100)

В чем причина этого исключения zipexception? моя версия apache poi - 3.17

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