Получить общее количество от текущего состояния запроса MySQL

Question

У меня проблема с подсчетом суммарных данных о текущем состоянии по запросу MySQL.

Вкратце, у меня есть 3 таблицы, которые связаны друг с другом.

m_shift_schedule     site_shift_schedule      m_ticket
================     ===================     ============
* shift_id   ======>  * shift_id             * ticket_id
* start_time          * shift_date           * ticket_status
* end_time            * user_id   ========>  * ticket_served_by

Мой запрос:

SELECT user_id,
case when count(m_ticket.ticket_served_by)<2 then 'idle' 
     when count(m_ticket.ticket_served_by)=2 then 'Busy' 
     when count(m_ticket.ticket_served_by)>2 then 'Overload' end as status
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
LEFT JOIN m_ticket ON site_shift_schedule.user_id=m_ticket.ticket_served_by
WHERE site_shift_schedule.shift_date =  '2019-02-11' and m_ticket.ticket_status in (4,5,6)
AND CURRENT_TIME > start_time and CURRENT_TIME < end_time
group by user_id

Мой вывод из вышеприведенного запроса:

user_id                           Status
=============================   ============
ismail.rahman.saanin@random.co     Idle
lutfi.aldi.nugroho@random.co       Busy

И вопрос: что мне делать, если я хочу, чтобы вывод стал таким:

 Status              Total
==================================
 Idle                 1
 Busy                 1

Answer 1

вариант использования, когда также в group by

SELECT 
case when count(m_ticket.ticket_served_by)<2 then 'idle' 
     when count(m_ticket.ticket_served_by)=2 then 'Busy' 
     when count(m_ticket.ticket_served_by)>2 then 'Overload' end as status,
     count(*) as total
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
LEFT JOIN m_ticket ON site_shift_schedule.user_id=m_ticket.ticket_served_by
WHERE site_shift_schedule.shift_date =  '2019-02-11' and m_ticket.ticket_status in (4,5,6)
AND CURRENT_TIME > start_time and CURRENT_TIME < end_time
group by  case when count(m_ticket.ticket_served_by)<2 then 'idle' 
     when count(m_ticket.ticket_served_by)=2 then 'Busy' 
     when count(m_ticket.ticket_served_by)>2 then 'Overload' end

Answer 2

Вы можете попробовать ниже - используя подзапрос

select status,count(user_id) as total
from
(
SELECT user_id,
case when count(m_ticket.ticket_served_by)<2 then 'idle' 
     when count(m_ticket.ticket_served_by)=2 then 'Busy' 
     when count(m_ticket.ticket_served_by)>2 then 'Overload' end as status
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
LEFT JOIN m_ticket ON site_shift_schedule.user_id=m_ticket.ticket_served_by
WHERE site_shift_schedule.shift_date =  '2019-02-11' and m_ticket.ticket_status in (4,5,6)
AND CURRENT_TIME > start_time and CURRENT_TIME < end_time
group by user_id
)A group by status