Продолжение предыдущего вопроса:)
Я полагаю, вы уже используете нумерацию строк (как и в предыдущем вопросе).
Итак, измените вашу процедуру обработки ошибок на что-то вроде:
Sub aa()
Dim zz As Long
10: On Error GoTo ErrorHandler
20: DivisionByZero = 1 / 0
30: Exit Sub
ErrorHandler:
41: If Err.Number <> 0 Then
42: Msg = "Error # " & Str(Err.Number) & " was generated by " _
& Err.Source & Chr(13) & "Error Line: " & Erl & Chr(13) & Err.Description
43: MsgBox Msg, , "Error", Err.HelpFile, Err.HelpContext
zz = CodeFind("", "", Str(Erl), 0)
44: End If
50: Resume Next
End Sub
Теперь о функции CodeFind ().Я нашел его здесь (внизу, последний), но мне пришлось немного его изменить, поэтому я публикую много кода ... извините.
Вставьте этокод в новом модуле и убедитесь, что у вас есть ссылка на «Microsoft Visual Basic For Applications Extensibility 5.3», и проект не защищен.В случае сомнений см. здесь .
HTH!
Вот код
Option Explicit
'---------------------------------------------------------------------------------------
' Procedure : CodeFind
' DateTime : 7/5/2005 18:32
' Author : Nelson Hochberg
' Purpose : Find a module, a procedure and/or a string in code and highlight it
' Returns : 0 if not found, line number in module if found
' Syntax : lngReturn = CodeFind ([FindMod],[FindProc],[FindStr],[TypeOfSearch])
' Arguments : Optional FindMod As String: Part of a name of a module
' Optional FindProc As String: Part of a name of a procedure
' Optional FindStr As String: Part of a string to search
' NOTE: One of the above three is required
' Optional TypeOfSearch As Long: -1 Find line number, 0 Find string,
' >0 Continue search starting at line number: TypeOfSearch + 1
' Thanks : To stevbe at Experts Exchange for the initial code.
'---------------------------------------------------------------------------------------
'
Public Function CodeFind( _
Optional FindMod As String = "", _
Optional FindProc As String = "", _
Optional FindStr As String = "", _
Optional TypeOfSearch As Long = 0 _
) As Long
Dim vbc As VBIDE.VBComponent
Dim cm As VBIDE.CodeModule
Dim VBAEditor As VBIDE.VBE
Dim VBProj As VBIDE.VBProject
Dim startline As Long, startcol As Long, endline As Long, endcol As Long
If FindMod <> "" Then
CodeFind = FindModule(FindMod, vbc, cm)
If CodeFind = False Then Exit Function
If FindProc <> "" Then
CodeFind = FindProcedure(FindProc, startline, startcol, endline, endcol, cm)
If CodeFind = False Then Exit Function
If FindStr <> "" Then
CodeFind = FindString(FindStr, startline, startcol, endline, endcol, cm, TypeOfSearch)
If CodeFind = False Then Exit Function
Else
GoTo CodeLineFound
End If
Else
startline = 1
If FindStr <> "" Then
CodeFind = FindString(FindStr, startline, startcol, endline, endcol, cm, TypeOfSearch)
If CodeFind = False Then Exit Function
Else
GoTo CodeLineFound
End If
End If
Else
Set VBAEditor = Application.VBE
'''''''''''''''''''''''''''''''''''''''''''
Set VBProj = VBAEditor.ActiveVBProject
For Each vbc In VBProj.VBComponents
Set cm = vbc.CodeModule
If FindProc <> "" Then
CodeFind = FindProcedure(FindProc, startline, startcol, endline, endcol, cm)
If CodeFind = False Then GoTo Nextvbc2 Else Exit For
Else
startline = 1
If FindStr <> "" Then
CodeFind = FindString(FindStr, startline, startcol, endline, endcol, cm, TypeOfSearch)
If CodeFind = False Then GoTo Nextvbc2 Else Exit For
Else
MsgBox "CodeFind: At least one of the following is required:" & vbCrLf & _
" Module" & vbCrLf & " Procedure" & vbCrLf & " String"
CodeFind = False
Exit Function
End If
End If
Nextvbc2:
Next vbc
If CodeFind <> False Then
If FindStr <> "" Then
CodeFind = FindString(FindStr, startline, startcol, endline, endcol, cm, TypeOfSearch)
If CodeFind = False Then Exit Function
Else
GoTo CodeLineFound
End If
End If
End If
CodeLineFound:
If CodeFind <> False Then
If endline = -1 Then endline = 1
If endcol = -1 Then endcol = 1
cm.CodePane.Show
cm.CodePane.SetSelection startline, startcol, endline, endcol
End If
End Function